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Alex_Xolod [135]
3 years ago
10

How is the number five and two hundred three thousandths written in standard form?

Mathematics
2 answers:
Andru [333]3 years ago
5 0

Answer:

0.05203*10 to the power 2

Step-by-step explanation:

To get the standard form you divide a number in order to multiply it by a power of 10 to get the same number. So 5.203 in standard form is o.o5203 * 10 to the power 2. The 10 to the power 2 comes from the number of palces you move the comma/ decimal point to the left

HOPE IT HELPED

sasho [114]3 years ago
4 0

Answer:

5.203

*I wrote the answer in decimal form*

When it says *and* that means u are adding a decimal point to ur number. Like this ( four and thirty-two hundredth = 4.32)

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kodGreya [7K]

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Slope = -2

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5 0
3 years ago
My common core lesson 7 3.1
Verizon [17]
What is the question?
5 0
3 years ago
There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
Y_Kistochka [10]

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

6 0
3 years ago
In a standard deck of cards, how many different sets of 4-of-a-kind are there?
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4 aces 4 twos 4 threes 4 fours 4 fives 4 sixes 4 sevens 4 eights 4 nines 4 tens
    1           2         3           4          5         6             7            8           9          10 
4 jacks 4 queens 4 kings
    11         12          13
The answer is 13 different sets.
I hope this helps :)

8 0
4 years ago
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Evgen [1.6K]

Answer:

the answer is x=99/20

Step-by-step explanation:

multiply both sides

6 0
4 years ago
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