The value of the angle shown in the protactor is 50° and the value of y is 10°.
<h3>How to calculate the values?</h3>
The value of y will be:
2y + 30 = 3y + 20
3y - 2y = 30 - 20
y = 10
The value of x when they're complementary will be:
5x - 2 + 3x + 4 = 90
8x + 2 = 90
8x = 90 - 2
8x = 88.
x = 88/8 = 12
The value of angle FDE will be:
3x + 10 + 6x + 8 = 180
9x + 18 = 180
9x = 180 - 18
9x = 162
x = 162/9
x = 18
FDE = 6x + 8
= 6(18) + 8
= 108 + 8
= 116
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Answer:
Assuming you mean (2^3)3, the answer is 24
Step-by-step explanation:
using pemdas you do 2 to the third power first
2x2=4 4x2=8
then you mutiply by the number not in parenthesis; 3
8x3 = 24
1.60 a note book. 6.40\4 assuming they are all the same notebook
Set the argument -1/2x equal to the x coordinate of the given point 6. Solve for x
-1/2x = 6
x = 6(-2)
x = -12
So x = -12 makes the equation -1/2x = 6 true.
If we plug x = -12 into f(-1/2x) we get f(6)
Since we know that (6,-8) is on the graph of f(x), we know that (-12,-8) is on the graph of f(-1/2x)
What happens is that there's a reflection over the y axis (due to the minus sign in -1/2x) and there's a horizontal stretch by a factor of 2. So the graph of f(-1/2x) appears to be wider than f(x).
In summary, the final answer is (-12,-8)
Width of the rectangle is 16 ft and length of the rectangle is 20 ft
<u>Step-by-step explanation:</u>
Step 1:
Given area of the rectangle = 320 ft². Let the width of the rectangle be x, then the length = x + 4. Use the formula for area of a rectangle = (length × width)
320 = x(x + 4)
320 = x² + 4x
x² + 4x - 320 = 0
x = (-b ±√b² - 4ac)/2a = (-4 ±√16 - 4×1×-320)/2
= (-4±√1296)/2 = (-4 ± 36)/2
= 32/2, -40/2 = 16, -20 (neglecting the negative value)
∴ Width of the rectangle = 16 ft
∴ Length of the rectangle = 16 + 4 = 20ft