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3 years ago

Zoom in and tell me the right answer and explain why..

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

7 0

It's probably 800 hope it's right

ValentinkaMS [17]3 years ago

6 0

I believe the answer is 800, although I could be wrong

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This is a sketch of the curve with equation y = f(x).

Katen [24]

Answer:

We have to use the formule to calculate the vertex which is: V(-b/2a;4ac-b^2/4a)

A) y=x+7 where a=1 b=0 and c=7

By replacing we have: V(0;28/4) V(0;7)

B) y=-x where a=-1 b and c=0 so V(0,0)

6 0

3 years ago

✨6 Grade Math✨ PLEASE HELP I RLLY DONT GET IT

ratelena [41]

Answer:

a. 12s + 19j - 3

36 + 28 - 3 = 61

Shirt (per unit cost):

Before Discount: $12

After Discount: $12 - $3 = $9

Jeans (pair cost):

Before Discount: $19

After Discount: $19 - $3 = $16

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8 0

3 years ago

Find the length of the following curve. If you have a grapher, you may want to graph the curve to see what it looks like.

stepladder [879]

The length of the curve $y = \frac{1}{27}(9x^2 + 6)^\frac 32$ from x = 3 to x = 6 is 192 units

<h3>How to determine the length of the curve?</h3>

The curve is given as:

$y = \frac{1}{27}(9x^2 + 6)^\frac 32$ from x = 3 to x = 6

Start by differentiating the curve function

$y' = \frac 32 * \frac{1}{27}(9x^2 + 6)^\frac 12 * 18x$

Evaluate

$y' = x(9x^2 + 6)^\frac 12$

The length of the curve is calculated using:

$L =\int\limits^a_b {\sqrt{1 + y'^2}} \, dx$

This gives

$L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx$

Expand

$L =\int\limits^6_3 {\sqrt{1 + x^2(9x^2 + 6)}\ dx$

This gives

$L =\int\limits^6_3 {\sqrt{9x^4 + 6x^2 + 1}\ dx$

Express as a perfect square

$L =\int\limits^6_3 {\sqrt{(3x^2 + 1)^2}\ dx$

Evaluate the exponent

$L =\int\limits^6_3 {3x^2 + 1} \ dx$

Differentiate

$L = x^3 + x|\limits^6_3$

Expand

L = (6³ + 6) - (3³ + 3)

Evaluate

L = 192

Hence, the length of the curve is 192 units