Using the expected value of a discrete distribution, it is found that the amount of points the player should lose for not rolling doubles in order to make this a fair game is of 1.
<h3>What is the expected value of a discrete distribution?</h3>The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.
In this problem, considering 6 out of 6^2 = 36 outcomes are doubles, we have that the distribution is:
P(X = 5) = 1/6.
P(X = x) = 5/6.
A fair game means that the expected value is of 0, hence:
The amount of points the player should lose for not rolling doubles in order to make this a fair game is of 1.
More can be learned about the expected value of a discrete distribution at brainly.com/question/24855677