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Gala2k [10]
3 years ago
13

The function y = 3 squared - x - 3 is graphed only over the domain of {x | –8 < x < 8}. What is the range of the graph?

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Answer: Y < = 144

Step-by-step explanation:

Given that the function y = 3 squared - x - 3 is graphed only over the domain of {x | –8 < x < 8}

That is, y = 3x^2 - 3

Since x is greater than -8, the minimum value of x will be -7.

Also, x is less than 8, the maximum value of x will be 7

Substitute the two values into the given function.

When x = -7

Y = 3(-7)^2 - 3

Y = 3(49) - 3

Y = 147 - 3

Y = 144

When x = 7

Y = 3(7)^2 - 3

Y = 3(49) - 3

Y = 147 - 3

Y = 144

The range of the graph is therefore, Y less than or equal to 144. That is,

Y < = 144

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It would he in quadrant 4

Step-by-step explanation:

First off you should know 2 represents x and -6 represents y since it is (x,y). To graph this we must find positive 2 on the x line which in the horizontal line. Then we must point -6. Since this term is negative, we move 6 points down since down is negative and up is positive.

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Yes I wanted to know what is the answer ​
jek_recluse [69]

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Step-by-step explanation:

First you would do 89/6 but since that doesn’t divide nicely you can do 90/6 to get 15 then subtract 1 since the original number was 89 and you would get 14

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3 years ago
Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

7 0
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kaheart [24]

Answer:

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Step-by-step explanation.

125 x 8 = 1000

.125 x 8 = 1

-.125 x 8 = -1

-1/8

8 0
3 years ago
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