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3 years ago

I need help plz! asap

Mathematics

1 answer:

nikdorinn [45]3 years ago

5 0

Answer:

B) 30

Step-by-step explanation:

too get a % of somthing all you need to do is convert 60% to a decimal .6 * 50 = <em><u>30</u></em>

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Help asappppp? i’m having trouble on wat the 1/4 point is

blagie [28]

Answer:

(-14, 5.5)

Step-by-step explanation:

Perhaps the easiest way to find the 1/4 point is to find (x, y), then find the midpoint between that and M.

(x, y) = 2M -(13, 25) = 2(-5, 12) -(13, 25) = (-23, -1)

Then the 1/4 point is ...

((-23, -1) +M)/2 = ((-23, -1) +(-5, 12))/2 = (-28, 11)/2 = (-14, 5.5)

_____

If we call the end points A(x, y) and B(13, 25), then we know ...

M = (A+B)/2

A = 2M -B . . . . we'll need this in a bit

and the 1/4 point Q is such that ...

(Q -A)/(B -A) = 1/4

4Q -4A = B -A . . . . cross multipliy

Q = (B +3A)/4 = (B +3(2M -B))/4 = (6M -2B)/4 . . . . solve for Q

Q = (3M -B)/2 . . . . reduce the fractions

Q = (3(-5, 12) -(13, 25))/2 = (-28, 11)/2 = (-14, 5.5) . . . as above

6 0

2 years ago

What is the answer to -x/3_>5

den301095 [7]

Answer: this is the answer

( {x}^{3} ) {}^{ - 5} = {x}^{ - 15}

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is y-intercept as an ordered pair (x,y) for y = 1/3x - 1 !!

user100 [1]

Answer:y=1

Step-by-step explanation:

5 0

2 years ago

What is the measure of ∠ADC?

Pachacha [2.7K]

Answer:

131

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

3 years ago