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RoseWind [281]
3 years ago
14

What is the equation of the circle with center (-6,7) that passes through the point (4,-2). A. (x+6)^2+(y-7)^2=181 B. (x-6)^2+(y

+7)^2=181 C. (x+6)^2+(y-7)^2=9 D. (x-6)^2+(y+7)^2=9
Mathematics
1 answer:
pychu [463]3 years ago
3 0
The equation of a cricle passing through (h,h) and with radius r is
(x-h)^2+(y-k)^2=r^2
so

cente ris (-6,7) and passing through (4,-2)
(x-(-6))^2+(y-7)^2=r^2
(x+6)^2+(y-7)^2=r^2
subsitute (4,-2) to find r^2

(4+6)^2+(-2-7)^2=r^2
(10)^2+(-9)^2=r^2
100+81=r^2
181=r^2

so it is

(x+6)^2+(y-7)^2=181
A is the answer
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