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cestrela7 [59]
3 years ago
7

1. The sum of four consecutive whole numbers is 110. What is the sum of the least and the greatest of the four numbers?

Mathematics
1 answer:
Trava [24]3 years ago
3 0

Answer:

55

Step-by-step explanation:

the four number is 26+27+28+29

so 26+29=55

You might be interested in
4 1/6 + 5 2/3Enter your answer as a mixed number in simplest form
galina1969 [7]

Answer:

Step-by-step explanation:

First, change the mixed numbers into improper fractions:

5 2/3 = 17/3

Then, find the common denominator:

41/6 + 17/3=

LCM = 6

17/3 *2 = 34/6

41/6 + 34/6

Last, Add

25/6  or

12 1/2

Hope this helps!

mark brainliest if possible!

3 0
2 years ago
Find the value of all trigonometric functions of 135°
Vera_Pavlovna [14]

Answer:

sin (- 135°)= – sin 135°= – sin (1 × 90°+ 45°) = – cos 45° = – 1√2

cos (- 135°)= cos 135°= cos (1 × 90°+ 45°) = – sin 45°= – 1√2

tan (- 135°) = – tan 135° = – tan ( 1 × 90° + 45°) = – (- cot 45°) = 1

csc (- 135°)= – csc 135°= – csc (1 × 90°+ 45°)= – sec 45° = – √2

sec (- 135°)= sec 135°= sec (1 × 90°+ 45°)= – csc 45°= – √2

cot (- 135°) = – cot 135° = – cot ( 1 × 90° + 45°) = – (-tan 45°) = 1

Step-by-step explanation:

hope this helps

5 0
1 year ago
Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab
Leviafan [203]

Answer:

z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936  

The p value can be founded with this formula:

p_v =P(z  

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

\bar X_{1}=7.6 represent the mean for Gibbs products

\bar X_{2}=8.1 represent the mean for the competitor

\sigma_{1}=2.3 represent the population standard deviation for Gibbs

\sigma_{2}=2.9 represent the sample standard deviation for the competitor

n_{1}=40 sample size for the group Gibbs

n_{2}=55 sample size for the group competitor

\alpha=0.05 Significance level provided

z would represent the statistic

Hypothesis to verify

We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}< 0  

The statistic would be given by:

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

Replacing the info given we got:

z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936  

The p value can be founded with this formula:

p_v =P(z  

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

5 0
3 years ago
Or the past 100 years, the average high temperature on october 1 is 78° with a standard deviation of 5°. what is the probability
valina [46]

Answer:

The probability is 0.683

Step-by-step explanation:

To calculate this, we shall be needing to calculate the z-scores of both temperatures

mathematically;

z-score = (x-mean)/SD

From the question mean = 78 and SD = 5

For 73

z-score = (73-78)/5 = -5/5 = -1

For 83

z-score = (83-78)/5 = 5/5 = 1

So the probability we want to calculate is within the following range of z-scores;

P(-1 <z <1 )

Mathematically, this is same as ;

P(z<1) - P(z<-1)

Using the normal distribution table;

P(-1<z<1) = 0.68269 which is approximately 0.683

3 0
3 years ago
The length of a Rectangle is 5M bigger than the width. The Perimeter is 150 a.m.. Find the width and the length
ZanzabumX [31]

Answer:

200 is the answer plz mark me

4 0
3 years ago
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