75 is 10 less than 85 what is the answer

Hank has to drain his pool so repairs can be done on a crack on the bottom. The company coming to fix the pool is scheduled to a

Alik [6]

Answer:

The answer to the question: "Will Hank have the pool drained in time?" is:

Yes, Hank will have the pool drained in time.

Step-by-step explanation:

To identify the time Hank needs to drain the pool, we can begin with the time Hank has from 8:00 AM to 2:00 PM in minutes:

Available time = 6 hours * 60 minutes / 1 hour (we cancel the unit "hour")
Available time = 360 minutes

Now we know Hank has 360 minutes to drain the pool, we're gonna calculate the volume of the pool with the given measurements and the next equation:

Volume of the pool = Deep * Long * Wide
Volume of the pool = 2 m * 10 m * 8 m
Volume of the pool = 160 m^3

Since the drain rate is in gallons, we must convert the obtained volume to gallons too, we must know that:

1 m^3 = 264.172 gal

Now, we use a rule of three:

If:

1 m^3 ⇒ 264.172 gal
160 m^3 ⇒ x

And we calculate:

$x = \frac{160 m^{3}*264.172 gal }{1m^{3} }$ (We cancel the unit "m^3)
x = 42267.52 gal

At last, we must identify how much time take to drain the pool with a volume of 42267.52 gallons if the drain rate is 130 gal/min:

Time to drain the pool = $\frac{42267.52gal}{130\frac{gal}{min} }$ (We cancel the unit "gallon")
Time to drain the pool = 325.1347692 minutes
Time to drain the pool ≅ 326 minutes (I approximate to the next number because I want to assure the pool is drained in that time)

As we know, Hank has 360 minutes to drain the pool and how it would be drained in 326 minutes approximately, we know Hank will have the pool drained in time and will have and additional 34 minutes.

7 0

3 years ago

What is the slope of the line represented by the equation? –2x + y = –1

Harrizon [31]

Isolate the y to one side so we get: y = 2x - 1
The slope of the line is 2.

8 0

2 years ago

Read 2 more answers

A soft-drink machine can be regulated so that it discharges an average of μ oz. per cup. If the ounces of fill are Normally dist

sattari [20]

Answer:

μ = 5.068 oz

Step-by-step explanation:

Normal distribution formula to use the table attached

Z = (x - μ)/σ

where μ is mean, σ is standard deviation, Z is on x-axis and x is a desired point.

98% of 6-oz. cups will not overflow means that the area below the curve is equal to 0.49; note that the curve is symmetrical respect zero, so, 98% of the cases relied between the interval (μ - some value) and (μ + some value)].

From table attached, area = 0.49 when Z = 2.33. From data, σ = 0.4 oz and x = 6 oz (maximum capacity of the cup). Isolating x from the formula gives

Z = (x - μ)/σ

2.33 = (6 - μ)/0.4

μ = 6 - 2.33*0.4

μ = 5.068

This means that with a mean of 5 oz and a standard deviation of 0.4 oz, the machine will discharge a maximum of 6 oz in the 98% of the cases.

4 0

3 years ago

Find thhe remainder when 7^203 is divided by 4

Aleksandr [31]

Using the square-and-multiply approach, we have

$7^{203}=7\times(7^{101})^2$
$7^{101}=7\times(7^{50})^2$
$7^{50}=(7^{25})^2$
$7^{25}=7\times(7^{12})^2$
$7^{12}=(7^6)^2$
$7^6=(7^3)^2$
$7^3=7\times7^2$

and so, using the property that, if $a_1\equiv b_1\mod n$ and $a_2\equiv b_2\mod n$ , then $a_1a_2\equiv b_1b_2\mod n$ , we get

$7\equiv3\mod4$
$7^2\equiv9\equiv1\mod4$
$7^3\equiv7\times1\equiv7\equiv3\mod4$
$7^6\equiv9\equiv1\mod4$
$7^{12}\equiv1\mod4$
$7^{25}\equiv7\times1\equiv7\equiv3\mod4$
$7^{50}\equiv9\equiv1\mod4$
$7^{101}\equiv7\times1\equiv7\equiv3\mod4$
$7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4$

4 0

3 years ago

Which expression is equivalent 5(2x-7) a.2x-25 b.7x-12 c.7x-12 d.10x-7 e.10x-35

Allushta [10]

Answer:

Your Answer is E. 10x-35

Step-by-step explanation:

Factor 10x−35

10x−35

=5(2x−7)

Answer:

5(2x−7)

3 0

3 years ago

Read 2 more answers