3 years ago

CAN SOMEONE PLEASEEE HELP SIMPLIFY THESE TWO EXPONENT PROBLEMS I HAVE NO CLUE HOW

Mathematics

1 answer:

Alecsey [184]3 years ago

6 0

Answer:

20. $-\frac{y^{12} }{9x^{4} }$

Step-by-step explanation:

21. $3 x^{2} y^{2}$

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3 years ago

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mash [69]

Answer:

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Step-by-step explanation:

$\huge \frac{x^2-3x-28}{(x^2+10x+24)(x-5)} \\\\\huge {=\frac{x^2-7x+4x-28}{(x^2+6x+4x+24)(x-5)}}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=\frac{(x-7)(x+4)}{(x+6)(x+4)(x-5)}}\\\\\huge {=\frac{(x-7)}{(x+6)(x-5)}}\\\\\huge {=\frac{(x-7)}{x^2+(6-5)x+6(-5)}}\\\\\huge {=\frac{(x-7)}{x^2+x-30}}$