Step-by-step explanation:
as the denominator (x+3) is in both you need only one denominator to be multiplied in first rational number .
<u>2</u><u>x</u><u> </u><u>(</u><u>x-2</u><u>)</u><u>. </u><u> </u><u> </u>+ <u>5</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u> </u>
(x+3) (x-2). (x+3) (x-2)
<u>2</u><u>x</u><u>^</u><u>2</u><u>-</u><u>4</u><u>x</u><u> </u><u>+</u><u>5</u><u> </u>
<u>(</u>x+3) (x-2)
it's cannot be solved after that.
number is described as rational if it can be written as a fraction (one integer divided by another integer). A number is irrational if it cannot be written as a fraction. The decimal form of an irrational number does not terminate or recur.
Answer:
Answers?
Step-by-step explanation:
Hopefully this is the correct answer i'm sorry if it's wrong.
Answer:
<em>-</em><em>1</em>
Step-by-step explanation:
<em>x</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>unknown</em><em> </em><em>and</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>known</em><em> </em><em>as</em><em> </em><em><u>1</u></em><em><u> </u></em><em>or</em><em> </em><em><u>-</u></em><em><u>1</u></em><em><u> </u></em><em>based</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>circumstance</em><em>.</em><em> </em>
<em>Therefore</em><em>,</em><em> </em><em>in</em><em> </em><em>this</em><em> </em><em>case</em><em>,</em><em> </em><em>x</em><em> </em><em>is</em><em> </em><em>known</em><em> </em><em>as</em><em> </em><em><u>-</u></em><em><u>1</u></em>
Let's read through this and make an equation:
? ("number")
? / -7 ("quotient of a number and -7")
(? / -7) - 2 ("decreased by 2")
<span>(? / -7) - 2 = 10 ("is 10")
</span>
Now we can solve:
<span>(? / -7) - 2 = 10
</span><span>? / -7 = 12
</span>? = -84
The number is -84
