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mestny [16]
4 years ago
8

I need help on this please

Mathematics
2 answers:
dangina [55]4 years ago
7 0

Answer:

4/7

Step-by-step explanation:

All you have to do is divide both sides by -14. It cancels out on the side with the y. And you get a simplified answer of 4/7 for your other side which is equal to the y.

Natali5045456 [20]4 years ago
3 0

Answer:

4/7

Step-by-step explanation:

1. In order to isolate y, you must divide -8 by -14.

2. -8/-14 --> 8/14 since the dividing two negatives gets you a positive

3. Simplify the fraction by dividing the top and bottom by 2

8/14 --> 4/7

Hope this helped :)

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.198/6= .033

.033x100= 3.3%

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Given vectors u = ⟨2, –3⟩ and v = ⟨1, –1⟩, what is the measure of the angle between the vectors?
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Answer:

The measure of the angle between the vectors = Ф = 11.30°

Step-by-step explanation:

Given

  • u = ⟨2, –3⟩
  • v = ⟨1, –1⟩

\mathrm{Computing\:the\:angle\:between\:the\:vectors}:\quad \cos \left(\theta \right)\:=\frac{\vec{a\:}\cdot \vec{b\:}}{\left|\vec{a\:}\right|\cdot \left|\vec{b\:}\right|}

Next, find the lengths of the vectors:

\mathrm{Computing\:the\:Euclidean\:Length\:of\:a\:vector}:\quad \left|\left(x_1\:,\:\:\ldots \:,\:\:x_n\right)\right|=\sqrt{\sum _{i=1}^n\left|x_i\right|^2}

u = ⟨2, –3⟩

\:\:\left|u\right|\:=\sqrt{2^2+\left(-3\right)^2}

     =\sqrt{13}

u = ⟨2, –3⟩

|v|=\sqrt{1^2+\left(-1\right)^2}

    =\sqrt{2}

Finally, the angle is given by:

\mathrm{Computing\:the\:angle\:between\:the\:vectors}:\quad \cos \left(\theta \right)\:=\frac{\vec{a\:}\cdot \vec{b\:}}{\left|\vec{a\:}\right|\cdot \left|\vec{b\:}\right|}

cos (Ф) = 5/√26

Ф = arc cos (cos (Ф)) = arc cos (5 √26) / (26)

Ф = 11.30°

Thus, the measure of the angle between the vectors = Ф = 11.30°

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