Answer:
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
Step-by-step explanation:
Since we have the radius of the sphere R = 4, we have R² = r² + z² where r = radius of cylinder in z-plane and z = height² of cylinder.
So, r = √(R² - z²)
r = √(4² - z²)
r = √(16 - z²)
Since the region is above the plane z = 2, we integrate z from z = 2 to z = R = 4
Our volume integral in cylindrical coordinates is thus
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
1. y+5=-x-5
2. y=-x-5-5
3.y=-x-10
4. y=x-10
_______________________
1. distribute negative sign
2. move the constant to the right and change the sign
3. -5-5 equals -10, bring everything down
4. change the sign of the x to positive, the equation is in standard form
With the formula: m=(y1-y2)/(x1-x2) you can sub in the values to get the slope (m).
m=(4-2)/(2-(-3))
= 2/5
Therefore the slope is 2/5.
<h2>
Answer:</h2>
C = 2πr
r = C/2π ...(1)
A = πr²
A = π(C/2π)² = πC²/4π²
A = C²/4π.
<u>Correct choice</u> - [A] A = C²/4π.
Answer:
first of all erase what u have written
Step-by-step explanation:
<h2>Q: 25-(3x+5)=2(x+8)+x</h2>
- 25-3x-5=2x+16+x
- 20-6x=16
- 6x=4
- x=2/3
