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svlad2 [7]
4 years ago
10

? is the change in position relative to an initial location

Physics
2 answers:
umka21 [38]4 years ago
7 0

Answer: c. displacement

Explanation:

Let's begin by stating clear that motion is the change of position of a body at a certain time. So, during this motion, the body will have a trajectory and a displacement.

In the specific case of the displacement, it is defined as the distance in a straight line between the initial and final position (is a vector magnitude).

Therefore:

Displacement s the the change in position relative to an initial location.

Elodia [21]4 years ago
6 0

Answer:

c: displacement

Explanation:

When a person moves from one point to another, the shortest distance between the two points in a straight line is what we call as the displacement. It is a vector quantity. Which means the change in position with respect to an initial position will be displacement.

Speed is a measure of change of distance relative to time. Velocity is a measure of change of displacement relative to time and acceleration is a measure of change of velocity relative to time.

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A 2.2 m -long wire carries a current of 7.2 A and is immersed within a uniform magnetic field B⃗ . When this wire lies along the
zimovet [89]

Answer:

Explanation:

Given that :

The current I =  7.2 A

The length vector L =   2.2 m i  

The force vector is = -2.6 j N

When L = 2.2 m i ; the

Force vector F = (2.6 i - 4.4 k) N

Compute the components of the magnetic field as follows:

F = I(L*B)

Replacing 7.2 A for I ; -2.6 j N for F & 2.2 m i for L

-2.6 j N = (7.2 A)(2.2 m i *(B_xi + B_yj+B_zk)

-2.6 j N = 15.84B_z \ and  \ 0 = 15.84B_y

B_z = -0.1641T  \ and \ B_y = 0

However in y direction ; we have :

(2.6 i - 4.4 k) = 7.2 A (2.2 mi*(B_xi+B_yj+B_zk)

- 2.6 = 15.84 B_z \ and \ -4.4 = 15.84 B_x

B_z = -0.1641 T \ and \ B_x = -0.2778T

Hence, the component of magnetic field is as follows:

B_x = -.02778T \ ; B_y = 0 T \  ; B_z =  - 0.1641 T)

5 0
3 years ago
A large truck and a compct car are both driving down the
koban [17]

Answer:

Explanation:

The friction force acting on the body depends on the mass of the body, here the mas of truck is very large as compared  to the car, so the friction force acting on the truck is large then the car. So, the amount of heat generated by the truck is more than the car and the truck overheated more.

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3 years ago
Why do teens need to eat more food than an older person?
Tanya [424]

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5 0
3 years ago
Read 2 more answers
a balloon rubbed against denim gains a charge of -8.0 x 10^-6 c. What is the electric force between the balloon and the denim, w
DedPeter [7]

Answer:

230.4 N

Explanation:

Applying,

F = kqq'/r²..................... Equation 1

Where F = Electric force, k = Coulomb's constant, q = charge in the ballon, q' =  charge in the denium, r = distance between the charges.

From the question,

Given: q = -8.0×10⁻⁶ C, q' = +8.0×10⁻⁶ C, r = 0.05 m

Constant: k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = (9×10⁹×8.0×10⁻⁶×8.0×10⁻⁶ )/0.05²

F = (576×10⁻³)/0.0025

F = 230.4 N.

6 0
3 years ago
A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 24.0° below the horizontal. The negligent
anzhelika [568]

Answer:

The position is  P  =  47.4 \ m relative to the base of the ocean

Explanation:

From the question we are told that

    The angle made by the incline with the horizontal is \theta =  24.0 ^o

    The constant acceleration is a =  3.82 \ m/s^2

    The distance covered is d =  60.0 \ m

    The height of the cliff is h  =  50 .0 \ m

The velocity of the car is mathematically represented as

      v^2 = u^2 +  2ad

The initial velocity of the car is  u= 0

So

     v^2 =  2ad

substituting values

     v^2 = 2 *  3.82 * 60

    v =  21.4 \ m/s

The vertical component of this velocity is

    v_v  =  -v * sin(\theta )

substituting values

    v_v  = -21.4 * sin(24.0)

    v_v  = -8.7 \ m/s

The negative sign is because is moving in the negative direction of the y-axis

The horizontal  component of this velocity is

     v_h  =  v * cos (\theta)

    v_h  =  21.4 * cos (24.0)

    v_h  = 19.5 \ m/s

Now according to equation of motion we have

     h  =  v_v*t  - \frac{1}{2} *  g t^2

substituting  values

    50  =  -8.7 t  - \frac{1}{2} *  9.8 t^2

    4.9t^2  +8.7t -50 = 0

using quadratic equation we have that

  t_1 = 2.42\ s \ and\   t_2 =  -4.20\ s

given that time cannot be negative

      t = 2.42 \ s

The  car’s position relative to the base of the cliff when the car lands in the ocean is mathematically evaluate as

           P  =  v_h * t

substituting values

          P  =  19.5 *  2.43

         P  =  47.4 \ m

5 0
3 years ago
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