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3 years ago

Could anyone help me on the questions of the Series Circuits please!!!! (The picture is attached)

Physics

1 answer:

strojnjashka [21]3 years ago

6 0

Series circuits - cpt connected so that the same current passes through each of them.
Disconnection/break in series circuit and current doesn't flow.
Current same
The total potential difference across all of the components. (the sum of the pds across the individual series elements).

The diagram in the enclosure seems to show resistors in parallel. Which is a bit confusing ...

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a scientist is creating a new synthetic material. the material’s density is 6.1 g/cm3. which sentences describe how the scientis

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6 0

3 years ago

Read 2 more answers

The resistance 2 Ω, 4 Ω and 8 Ω are connected in parallel. Their equivalent

Zigmanuir [339]

Answer:

The answer to your question is the letter B. R = 8/7 Ω

Explanation:

Data

R1 = 2 Ω

R2 = 4Ω

R3 = 8Ω

To calculate the total resistance use the formula

1/R = 1/R1 + 1/R2 + 1/R3

-Substitution

1/R = 1/2 + 1/4 + 1/8

- Look for the Greatest common factor

2 4 8 2

1 2 4 2

1 2 2

The GCF = 2 x 2 x 2 = 8

-Sum up the fractions

1/2 + 1/4 + 1/8 = (4 + 2 + 1) / 8

= 7/8

-Find R

1/R = 7/8 then, R = 8/7 Ω

3 0

3 years ago

Can anyone explain and get the answer pls?

Veronika [31]

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3 years ago

A light ray incident from medium 1 to medium 2, where n1>n2. When the incident angle exceed the critical angle ac, the refrac

vovikov84 [41]

Explanation:

(a)

Critical angle is the angle at the angle of refraction is 90°. After the critical angle, no refraction takes place.

Using Snell's law as:

$n_1\times {sin\theta_i}={n_2}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence

${\theta_r}$ is the angle of refraction = 90°

${n_2}$ is the refractive index of the refraction medium

${n_1}$ is the refractive index of the incidence medium

Thus,

$n_1\times {sin\ \theta_{critical}}={n_2}\times{sin\ 90^0}$

The formula for the calculation of critical angle is:

${sin\theta_{critical}}=\frac {n_2}{n_1}$

Where,

${\theta_{critical}}$ is the critical angle

(b)

No it cannot occur. It only occur when the light ray bends away from the normal which means that when it travels from denser to rarer medium.

7 0

4 years ago

A mass spectrometer is being used to monitor air pollutants. it is difficult, however, to separate molecules with nearly equal m

Fynjy0 [20]

Answer:

The answer is 1250 mm

Explanation:

The path that particles move in the spectrometer is semicircular. Each of the particles has a displacement of twice the radius (2r) from the entrance to where the film is hit. According to the exercise, if the separation between the two molecules is 0.25 mm, then the difference in the radius of the molecules is equal to 0.125 mm. The ratio of mass/radius is equal for molecules, and therefore is equal to:

m = q * B * r / v

m/r = constant

(m/r)CO = (m/r)N = (28.0106 u/r) = (28.0134 u/(r + 0.000125 m))

Clearing and solving r:

r = 1.25 m = 1250 mm

4 0

3 years ago