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3 years ago

What is the net force needed to lift a full grocery sack weighing 210N uniformly?

1 answer:

Alex3 years ago

8 0

If the sack weighs 210 newtons, then an upward force of 210 newtons
exactly cancels the downward force of gravity, and makes the net vertical
force on the bag zero.

ANY upward force that's greater than 210 newtons makes the net force
act upward on the bag, and causes it to accelerate upward.

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If a typical smelt weighs 225 g, what is the total mass of pcbs in a smelt in the great lakes? If a typical smelt weighs 225 g,

photoshop1234 [79]

Answer;

= 2.34 x 10^-4 g pcbs

Explanation;

-A typical smelt has 1.04 ppm of PCB is great lakes.

Therefore;

The amount of PCB in a smelt in great leak can be calculated by multiplying the mass of smelt by the pcbs present in a smelt

= 225 g * ( 1.04/100000)

= 2.34 x10^-4 g pcbs

7 0

3 years ago

A block of mass 10kg is moved at a constant speed through a horizontal distance of 4m, by applying a force 50N. How much work ha

algol13

Answer:

Explanation:

given that

mass = 10kg

distance = 4m

force = 50N

to calculate the workdone when the force is applied in the same direction of displacement

mathematically,

workdone = force × distance

Workdone = 50 × 4

workdone = 200 joules

2) to calculate the workdone at an angle of 30° with the displacement we apply the formula

workdone = force × distance × cos Ф

workdone = 50 × 4 × cos 30°

workdone = 200 × 0.866

workdone = 173 . 2 joules

4 0

3 years ago

If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius is: A. 705Â°C. B. 873Â°C. C. 273Â°C. D. 327Â°C

zlopas [31]

Answer:

D). $327 ^0 C$

Explanation:

As we know that temperature scale is linear so we will have

$\frac{^0C - 0}{100 - 0} = \frac{K - 273}{373 - 273}$

now we have

$\frac{^0 C - 0}{100} = \frac{K - 273}{100}$

so the relation between two scales is given as

$^0 C = K - 273$

now we know that in kelvin scale the absolute temperature is 600 K

so now we have

$T = 600 - 273 = 327 ^0 C$

so correct answer is

D). $327 ^0 C$

4 0

3 years ago

Falling objects drop with an average acceleration of 9.8 m/s2. An arrow is shot with a velocity of 11.76 m/s straight down from

In-s [12.5K]

Answer:

3.8 secs

Explanation:

Parameters given:

Acceleration due to gravity, g = 9.8 $m/s^2$

Initial velocity, u = 11.76 m/s

Final velocity, v = 49 m/s

Using one of Newton's equations of linear motion, we have that:

$v = u + gt$

where t = time of flight of arrow

The sign is positive because the arrow is moving downward, in the same direction as gravitational force.

Therefore:

$49 = 11.76 + 9.8*t\\\\\\\49 - 11.76 = 9.8t\\\\=> 9.8t = 37.24\\\\\\t = \frac{37.24}{9.8} \\\\\\t = 3.8 secs$

The arrow was in flight for 3.8 secs

6 0

3 years ago

A 6,600 kg train car moving at +2.0 m/s bumps into and locks together with one of mass 5,400 kg moving at -3.0 m/s.

Katarina [22]

Option B would be right one
according to momentum conservation
6600*2 = 13200kgm/s
5400*3 = 16200kgm/s
16200-13200 = 3000
now 6600-5400 = 1200 kg
thus 3000/1200 = 2.5 v

5 0

3 years ago