All categories

3 years ago

3 2/6 + ( 2 1/6 + 4/6 )

Mathematics

1 answer:

stellarik [79]3 years ago

3 0

Answer:

5 7/6 or 6 1/6 either one works they are the same number just one is not simplified

You might be interested in

95i is a root of f(x)=x^2 +9025. find the other roots of f(x)

Alex_Xolod [135]

Answer:

Other root is -95i

Step-by-step explanation:

Here, Nature of roots of f(x) is imaginary roots.

Therefore, Roots are conjugate of each other.

Conjugate of x + yi is x - yi.

we get conjugate of 95i as -95i

Verification shows....

(x-95)(x+95i)=0

${x }^{2} - {95}^{2} {i}^{2} = 0 \\ {x }^{2} + {95}^{2} = 0 \\ {x }^{2} + 9025= 0 \\ f(x) = 0$

this, roots are -95i and 95i

5 0

3 years ago

Why is 12 inches 1 foot a conversion factor ?

Alinara [238K]

I have no better answer than simply, because there are 12 inches in a foot.

By definition a conversion factor is one unit being used to express a group or multiple of another unit. Just like how there are 12 of anything in one dozen. 100 years in one century. 365 days in one year. 100 centimeters in a meter. 4 quarts in one gallon. 10 dimes in one dollar. They are equal to each other and, thus, can be used as conversion factors.

3 0

3 years ago

The function f(x) = −(x + 5)(x + 1) is shown. What is the range of the function? all real numbers less than or equal to 4 all re

Tpy6a [65]

all real numbers such that y is less than or equal to 4

6 0

3 years ago

Read 2 more answers

Which pair of points on a coordinate plane are separated by a distance of 5 units?

icang [17]

Answer:

(0,0) and (5,0)

Step-by-step explanation:

i dont know your choices

5 0

3 years ago

A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest

faltersainse [42]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73$

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396$

add both amounts, and that's her investment for the 11 years.

7 0

3 years ago