Answer:
y = 28
Step-by-step explanation:
Given that y varies directly as x and inversely as z then the equation relating them is
y =
← k is the constant of variation
To find k use the condition y = 4 when x = 2 and z = 7, then
4 =
( multiply both sides by 7 )
28 = 2k ( divide both sides by 2 )
14 = k
y =
← equation of variation
When x = 6 and z = 3 , then
y =
= 14 × 2 = 28
Answer:
true true flase
Step-by-step explanation:
Answer:
7.5 kilograms of apples
Step-by-step explanation:
Take the total amount and subtract the amount of pears.
8.9-1.4=7.5
The numbers of chairs and tables that should be produced each week in order to maximize the company's profit is 15 chairs and 18 tables.
Since a furniture company has 480 board ft of teak wood and can sustain up to 450 hours of labor each week, and each chair produced requires 8 ft of wood and 12 hours of labor, and each table requires 20 ft of wood and 15 hours of labor, to determine, if a chair yields a profit of $ 65 and a table yields a profit of $ 90, what are the numbers of chairs and tables that should be produced each week in order to maximize the company's profit, the following calculation should be done:
- 16 chairs; 24 tables
- Time used = 16 x 12 + 24 x 15 = 192 + 360 = 552
- Wood used = 16 x 8 + 24 x 20 = 128 + 480 = 608
- 15 chairs; 18 tables
- Time used = 15 x 12 + 18 x 15 = 180 + 270 = 450
- Wood used = 15 x 8 + 18 x 20 = 120 + 360 = 480
- 12 chairs; 28 tables
- Time used = 12 x 12 + 28 x 15 = 144 + 420 = 564
- Wood used = 12 x 8 + 28 x 20 = 96 + 540 = 636
- 18 chairs; 20 tables
- Time used = 18 x 12 + 20 x 15 = 216 + 300 = 516
- Wood used = 18 x 8 + 20 x 20 = 144 + 400 = 544
Therefore, the only option that meets the requirements of time and wood used is that of 15 chairs and 18 tables, whose economic benefit will be the following:
- 15 x 65 + 18 x 90 = X
- 975 + 1,620 = X
- 2,595 = X
Therefore, the numbers of chairs and tables that should be produced each week in order to maximize the company's profit is 15 chairs and 18 tables.
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See the graph in the attached image.