Answer:
the first is 12
18
5.1
4 tulips per minute
9.50
Step-by-step explanation:
PLZ BRAinlest
Answer: 
Step-by-step explanation:
Given
The volume of the spherical solid is 
It is melted to form a solid cube
Suppose the edge length of the cube is 
The volume of the sphere is 
![\Rightarrow 123,456=a^3\\\Rightarrow a^3=123,456\\\text{Factorising 123,456}\\\Rightarrow a^3=2^6\times 3\times 643\\\\\Rightarrow a=\sqrt[3]{2^6\times 3\times 643} \\\\\Rightarrow a=4\sqrt[3]{ 3\times 643}\\\\\Rightarrow a=49.79\ m](https://tex.z-dn.net/?f=%5CRightarrow%20123%2C456%3Da%5E3%5C%5C%5CRightarrow%20a%5E3%3D123%2C456%5C%5C%5Ctext%7BFactorising%20123%2C456%7D%5C%5C%5CRightarrow%20a%5E3%3D2%5E6%5Ctimes%203%5Ctimes%20643%5C%5C%5C%5C%5CRightarrow%20a%3D%5Csqrt%5B3%5D%7B2%5E6%5Ctimes%203%5Ctimes%20643%7D%20%5C%5C%5C%5C%5CRightarrow%20a%3D4%5Csqrt%5B3%5D%7B%203%5Ctimes%20643%7D%5C%5C%5C%5C%5CRightarrow%20a%3D49.79%5C%20m)
Answer:Lateral Surface Area is 672m^2
Step-by-step explanation:
Surface Area of Triangles= 8m*12m=96
Surface Area of Top & Bottom Rectangles= 12m*18m*2=432m^2
Surface Area of Middle Triangle=12m*18m=216
Total Surface Area= 216+432+96
672m^2
Well lets start with the one hour part- 1 hour added on to 8:10 is 9:10 + 53min. is 10:03 so calls finished mowing the lawn at 10:03 am.
Answer:
A) Radius: 3.44 cm.
Height: 6.88 cm.
B) Radius: 2.73 cm.
Height: 10.92 cm.
Step-by-step explanation:
We have to solve a optimization problem with constraints. The surface area has to be minimized, restrained to a fixed volumen.
a) We can express the volume of the soda can as:

This is the constraint.
The function we want to minimize is the surface, and it can be expressed as:

To solve this, we can express h in function of r:

And replace it in the surface equation

To optimize the function, we derive and equal to zero
![\frac{dS}{dr}=512*(-1)*r^{-2}+4\pi r=0\\\\\frac{-512}{r^2}+4\pi r=0\\\\r^3=\frac{512}{4\pi} \\\\r=\sqrt[3]{\frac{512}{4\pi} } =\sqrt[3]{40.74 }=3.44](https://tex.z-dn.net/?f=%5Cfrac%7BdS%7D%7Bdr%7D%3D512%2A%28-1%29%2Ar%5E%7B-2%7D%2B4%5Cpi%20r%3D0%5C%5C%5C%5C%5Cfrac%7B-512%7D%7Br%5E2%7D%2B4%5Cpi%20r%3D0%5C%5C%5C%5Cr%5E3%3D%5Cfrac%7B512%7D%7B4%5Cpi%7D%20%5C%5C%5C%5Cr%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B512%7D%7B4%5Cpi%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B40.74%20%7D%3D3.44)
The radius that minimizes the surface is r=3.44 cm.
The height is then

The height that minimizes the surface is h=6.88 cm.
b) The new equation for the real surface is:

We derive and equal to zero
![\frac{dS}{dr}=512*(-1)*r^{-2}+8\pi r=0\\\\\frac{-512}{r^2}+8\pi r=0\\\\r^3=\frac{512}{8\pi} \\\\r=\sqrt[3]{\frac{512}{8\pi}}=\sqrt[3]{20.37}=2.73](https://tex.z-dn.net/?f=%5Cfrac%7BdS%7D%7Bdr%7D%3D512%2A%28-1%29%2Ar%5E%7B-2%7D%2B8%5Cpi%20r%3D0%5C%5C%5C%5C%5Cfrac%7B-512%7D%7Br%5E2%7D%2B8%5Cpi%20r%3D0%5C%5C%5C%5Cr%5E3%3D%5Cfrac%7B512%7D%7B8%5Cpi%7D%20%5C%5C%5C%5Cr%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B512%7D%7B8%5Cpi%7D%7D%3D%5Csqrt%5B3%5D%7B20.37%7D%3D2.73)
The radius that minimizes the real surface is r=2.73 cm.
The height is then

The height that minimizes the real surface is h=10.92 cm.