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sasho [114]
3 years ago
13

Jack is a farmer and he wants to know the average weight of all the potatoes in a sack. He randomly selects 10 potatoes and weig

hs them. Their weights, to the nearest ounce are 5, 8, 9, 11, 7, 7, 8, 9, 12, and 7. What is the best estimate of the average weight of all the potatoes in the sack? Round to the nearest ounce.
Mathematics
1 answer:
Maurinko [17]3 years ago
7 0
Jack should remove the maximum and minimum weight potatoes from the average weight of the potatoes to compensate for the extremes. Therefore, we are left with a data set of:
8, 9, 11, 7, 7, 8, 9, 7; so n = 8
The sum of these is 66
The average weight of each potato is:
66/8
= 8 ounces
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Read 2 more answers
What is the value of this expression when c = -4 and d = 10?
lianna [129]

The complete question is

"What is the value of this expression when c= -4 and d= 10?

1/4 (c^3+d²)

A.2

B.9

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The value of this expression when c = -4 and d = 10 will be option B 9.

<h3>What is a simplification of an expression?</h3>

Usually, simplification involves proceeding with the pending operations in the expression.

Simplification usually involves making the expression simple and easy to use later.

The given expression is

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Solve.
Nikitich [7]
The answer is C: 10\text{ }^1/_2. Here are the details:

\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add 'em up!}\\&#10;16\text{ }^5/_6

\text{Equation:}\\&#10;16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Start with the integers.}\\&#10;16+3=19\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{...then with the fractions, but rewrite them first to make it easier.}\\&#10;^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add 'em up!}\\&#10;20\text{ }^2/_3

\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add the integer and fraction together.}\\&#10;25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6

26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6
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