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Rudik [331]
3 years ago
15

At the start of summer, Joan got haircut that took off 1 ¾ inches. By the end of the summer, her hair had grown 1 ¾ inches. What

is the overall increase or decrease to Joan's hair in inches?​
Mathematics
1 answer:
Orlov [11]3 years ago
4 0

Answer:

There's no increase

Step-by-step explanation:

She got the same inches grown as the same she took off

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How many 0.3's would it take to make 3? Explain your reasoning. ​
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10. Since it you want to find how many 0.3s it would take to make 3, you would divide 3 by 0.3 or move the decimal over one spot to the right making it 10.
3 0
3 years ago
Derivative of this function<br> <br>Y= -7X³ -8X² +6X +3
zaharov [31]

In general, the derivative of a single term  Ax^(n)  is  A n x^(n-1) .

And the derivative of a sum of many terms is the sum of the derivatives
of the individual terms.  

Using these two rules, the derivative (with respect to 'x') of the expression
in the question is . . .

<em>            Y' = -21x² - 16x + 6</em>


7 0
3 years ago
What are the side lengths of the equilateral triangle?
Alchen [17]

5x  +  (6x - 5) + (3x + 10) = 360

5x  + 6x - 5 + 3x + 10 = 360

11x - 5 + 3x + 10 = 360

14x + 5 = 360

14x = 360 - 5

14x = 355

x = 25.36

<h2><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u></h2>

x = 25.36

5x = 5 \times 25.36 = 126.8

6x - 5 = 6 \times 25.36 - 5 = 147.16

3x + 10 = 3 \times 25.36 + 10 = 86.08

4 0
3 years ago
CCA has stated in 2017 that 36.5 % of its students are first generation college students.Suppose you sample 15 CCA students and
nignag [31]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - p) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 36.5% = 36.5/100 = 0.365

q = 1 - p = 1 - 0.365

q = 0.635

n = 15

a) P(x = 0) = 15C0 × 0.365^0 × 0.635^(15 - 0) = 0.0011

P(x = 1) = 15C1 × 0.365^1 × 0.635^(15 - 1) = 0.0095

P(x = 2) = 15C2 × 0.365^2 × 0.635^(15 - 2) = 0.038

P(x = 3) = 15C3 × 0.365^3 × 0.635^(15 - 3) = 0.095

P(x = 4) = 15C4 × 0.365^4 × 0.635^(15 - 4) = 0.16

P(x = 5) = 15C5 × 0.365^5 × 0.635^(15 - 5) = 0.21

k P(X = k)

0 0.0011

1 0.0095

2 0.038

3 0.095

4 0.16

5 0.21

b) mean = np = 15 × 0.365 = 5.475

c) standard deviation = √npq

= √15 × 0.365 × 0.635

= 1.86

d) z = (x - mean)/standard deviation

x = 2

z = (2 - 5.475)/1.86 = - 1.87

6 0
3 years ago
As the number of degrees of freedom for a t distribution increases. True or False
valkas [14]

Answer:

t distribution behaves like standard normal distribution as the number of freedom increases.

Step-by-step explanation:

The question is missing. I will give a general information on t distribution.

t-distribution is used instead of  normal distribution when the <em>sample size is small (usually smaller than 30) </em>or <em>population standard deviation is unknown</em>.

Degrees of freedom is the number of values in a sample that are free to vary. As the number of degrees of freedom for a t-distribution increases, the distribution looks more like normal distribution and follows the same characteristics.

7 0
4 years ago
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