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3 years ago

What is the quotient of (x3 - 3x2 + 5x – 3) = (x - 1)?

Mathematics

2 answers:

IRINA_888 [86]3 years ago

7 0

Note: Consider "÷" sign instead of "=".

Given:

$(x^3-3x^2+5x-3)\div (x-1)$

To find:

The quotient.

Solution:

We have,

$(x^3-3x^2+5x-3)\div (x-1)$

It can be written as

$=\dfrac{x^3-3x^2+5x-3}{x-1}$

Splitting the middle terms, we get

$=\dfrac{x^3-x^2-2x^2+2x+3x-3}{x-1}$

$=\dfrac{x^2(x-1)-2x(x-1)+3(x-1)}{x-1}$

Taking out the common factor (x-1), we get

$=\dfrac{(x-1)(x^2-2x+3)}{x-1}$

Cancel the common factors.

$=x^2-2x+3$

The quotient is $x^2-2x+3$ .

Therefore, the correct option is D.

algol [13]3 years ago

6 0

Answer:

Step-by-step explanation:

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8. 36.8 = [11.5 – (2.5 X 3)]2

Anestetic [448]

Answer:

$[11.5-(2.5*3)]^2=16$

Step-by-step explanation:

We want to evaluate $[11.5-(2.5*3)]^2$

Let us evaluate within the parenthesis first:

$[11.5-(2.5*3)]^2=[11.5-(7.5)]^2$

$\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2$

We again subtract within the bracket to obtain:

$[11.5-(2.5*3)]^2=[4]^2$

This finally gives us:

$[11.5-(2.5*3)]^2=16$

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3 years ago

What's the value of 125.009-2.3

marta [7]

Step-by-step explanation:

just subtract it

answer is 122.709

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3 years ago

benito read 14 books in 3 months, which was 35% of the number of books he had signed up to read during the school year .how many

lianna [129]

14 books in 3 months is 35%
all of books is 100%

14- 35%
x- 100%
we calculate from proportions, crosswise:
$x=\frac{14*100}{35}=\frac{1400}{35}=40$

Answer: Benito sign up to read 40 books.

Greetings,
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7 0

3 years ago

There are 20 machines in a factory. 7 of the machines are defective.

adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

4 0

3 years ago

Need answer for this ratios question

Tom [10]

Answer: 4:1

Step-by-step explanation: I think the answer is 4:1. I think this because 20% of 2500, would be 500. So 2500-500=2000. So the ratio would be 2000:500. Then we simplify 2000:500, by dividing 2000 by 500, and dividing 500 by 500. 500 / 500 = 1. 2000 / 500 = 4, so the answer is 4:1. (I am sorry if I am incorrect)

7 0

2 years ago