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sergey [27]
2 years ago
15

What is the quotient of (x3 - 3x2 + 5x – 3) = (x - 1)?

Mathematics
2 answers:
IRINA_888 [86]2 years ago
7 0

Note: Consider "÷" sign instead of "=".

Given:

(x^3-3x^2+5x-3)\div (x-1)

To find:

The quotient.

Solution:

We have,

(x^3-3x^2+5x-3)\div (x-1)

It can be written as

=\dfrac{x^3-3x^2+5x-3}{x-1}

Splitting the middle terms, we get

=\dfrac{x^3-x^2-2x^2+2x+3x-3}{x-1}

=\dfrac{x^2(x-1)-2x(x-1)+3(x-1)}{x-1}

Taking out the common factor (x-1), we get

=\dfrac{(x-1)(x^2-2x+3)}{x-1}

Cancel the common factors.

=x^2-2x+3

The quotient is x^2-2x+3.

Therefore, the correct option is D.

algol [13]2 years ago
6 0

Answer:

D

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 0
2 years ago
A 16 ounce bag of cereal cost $2.88 what is the cost per ounce
BabaBlast [244]

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5 0
2 years ago
What is the cost of operating a 3.00-w electric clock for a year if the cost of electricity is $0.0900 per kw · h ?
brilliants [131]
We must take into account the following change of units:
 1kw = 1000w

1 year = 365 days

1 day = 24 hours
 Applying the change of units we have that the electric consumption for 1 year is given by:
 (3) * (1/1000) * (365) * (24) = 26.28 kw * h

 Then, the total cost is given by:
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 Answer:
 
the cost of operating a 3.00-w electric clock for a year is:
 
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8 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
marissa [1.9K]

Answer:

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

Step-by-step explanation:

If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -

x = ( 30 cos 20° )( time ),

y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2

To determine " ( 30 cos 20° )( time ) " you would do the following calculations -

( x = 30 * 0.93... = ( About ) 28.01t

This represents our horizontal distance, respectively the vertical distance should be the following -

y = 30 * 0.34 - 4.9t^2,

( y = ( About ) 10.26t - 4.9t^2 + 2

In other words, our solution should be,

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

<u><em>These are are parametric equations</em></u>

5 0
3 years ago
A point located at (6, -4) is reflected over the x-axis. What are the coordinates of the image?
frutty [35]
It will be (6,4) all u do is slip it over t he x-axis
3 0
3 years ago
Read 2 more answers
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