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Sidana [21]
2 years ago
11

Find the value of the ratio. Can someone help please???

Mathematics
1 answer:
USPshnik [31]2 years ago
3 0

Answer:

SOH CAH TOA.....Cosine=adj/hyp...... __cosX=16/30___

SOH CAH TOA,,,,,, Tangent= opp/adj-------- Tan X=36/27

Step-by-step explanation:

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Solve the following equations putting them in slope intercept form. Then
asambeis [7]

Answer:

1. slope  is -1 and y intercept is 2

3. slope is -2 and y intercept is -4

2. slope is -4 and y intercept is 2

4. this is not a line - it is a parabola

Step-by-step explanation:

1. -4y = 4x -8

y = -x + 2

3. 4y = -8x -16

y = -2x - 4

2. y = -4x + 2

4. y - 14 = -3x^2 -16x

y = 3x^2 - 16x + 4

7 0
2 years ago
What multiples of 4 are not factors of 48?
drek231 [11]
48 = 48 * 1 = 24 * 2 = 16 * 3 = 12 * 4 = 8 * 6
So the factors of 48 are: 1, 2, 3, 4, 6, 89, 12, 16, 24 and 48.
The multiples of 4 are: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48,...
Answer:
Multiples of 4 that are not factors of 48 are: 20, 28, 32, 36, 40, 44.
3 0
3 years ago
Read 2 more answers
PLZ HELP ME ITS DUE TOMORROW!!!!!!!
kotykmax [81]

Answer:option a

Step-by-step explanation:multiply all values with 5:

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4 0
2 years ago
Consider the function f(x)=(x-9)/(x^3-81x)<br><br> Find the vertical asymptote(s) of f(x)
enyata [817]
Well, here's a harder one
Basically, to find a vertical asymptote, we set the denominator to 0. Like this:
x^3 - 81x = 0
Then we solve for x.
x(x^2 - 81) = 0
x(x+9)(x-9) = 0
x = 0, 9, -9
There are vertical asymptotes at x = 0, x = 9, and x = -9.

4 0
3 years ago
Read 2 more answers
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Oduvanchick [21]
The answer is (5.5,-6.5) because you find the midpoint for the x-axis which is 9+2 then divide by 2 then do the same for the y-axis and place them together.
6 0
3 years ago
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