Explanation:
Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions.
Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes reduction reactions.
When oxidizing agent-A get reduced it changes green to colorless.
When oxidizing agent-B get reduced it changes yellow to colorless.
When oxidizing agent-C get reduced it changes red to colorless.
1) When we added solution C that oxidizing agent-C in solution containing 
ions changes from red to yellow:
So, in this C is oxidizing ion into B which yellow in color.
C is reduced and ions is oxidized.
Here, are oxidized by C which means that C a better oxidizing agent than B.
2) When a solution of C is mixed with one containing A- ions, the color remains red.
no reaction
As we had observed that no color change was seen on adding substance C to the solution with 
ions which indicates that C was unable to oxidize ions. Hence, not a better oxidizing agent than A
The answer to this is true.
Answer:
a) 12/323
b) 8/233
Explanation:
a) The probability of a red ball being drawn is 12/38, or in a simplified fraction, 6/19. To find the probability that 3 are red you would multiply the probability of the fraction for each, except subtracting one from the total each time as the drawn is done without replacement. This is done as follows: 6/19 × 6/18 × 6/17= 12/323
b) The probability of drawing a blue ball is 8/38, or 4/19. To find that the first one is blue and the rest are red, the equation is done as follows: 4/19 × 6/18 × 6/17 = 8/233
(hopefully I did this right)
Answer:
The answer to your question is given after the questions so I just explain how to get it.
Explanation:
a)
Get the molecular weight of Phosphoric acid
H₃PO₄ = (3 x 1) + (31 x 1) + (16 x 4)
= 3 + 31 + 64
= 98 g
98 g ----------------- 1 mol
0.045 g --------------- x
x = (0.045 x 1) / 98
x = 0.045 / 98
x = 0.00046 moles or 4.6 x 10 ⁻⁴
b)
Molarity = 
Molarity = 
Molarity = 0.0013 or 1.31 x 10⁻³
c)
Formula C₁V₁ = C₂V₂
V₁ = C₂V₂ / C₁
Substitution
V₁ = (0.0013)(1) / 0.01
Simplification and result
V₁ = 0.0013 / 0.1
V₁ = 0.13 l = 130 ml
Answer:
1.23 moles
Explanation:
Ideal gas law
PV = n RT R = .082057 L-atm/mol-K
25 C = 298.15 K
12 (2.5) = n (.082057) (298.15) n = 1.23 moles
