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denpristay [2]
3 years ago
5

Substances A, B, and C can all act as oxidizing agents. In solution, A is green, B is yellow, and C is red. In the reactions in

which they participate, they are reduced to A-, B-, and C- ions, all of which are colorless. When a solution of C is mixed with one containing B- ions, the color changes from red to yellow.Which species is oxidized? Which is reduced?When a solution of C is mixed with one containing A- ions, the color remains red.Is C a better oxidizing agent than A?Is C a better oxidizing agent than B?
Chemistry
1 answer:
igor_vitrenko [27]3 years ago
3 0

Explanation:

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions.

Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes reduction reactions.

When oxidizing agent-A get reduced it changes green to colorless.

A+e^-\rightarrow A^-

When oxidizing agent-B get reduced it changes yellow to colorless.

B+e^-\rightarrow B^-

When oxidizing agent-C get reduced it changes red to colorless.

C+e^-\rightarrow C^-

1) When we added solution C that oxidizing agent-C in solution containing B^- ions changes from red to yellow:

C+B^-\rightarrow C^-+B(yellow)

So, in this C is oxidizing B^- ion into B which yellow in color.

C is reduced and B^- ions is oxidized.

Here, B^- are oxidized by C which means that C a better oxidizing agent than B.

2) When a solution of C is mixed with one containing A- ions, the color remains red.

C+A^-\rightarrow no reaction

As we had observed that no color change was seen on adding substance C to the solution with A^- ions which indicates that C was unable to oxidize A^- ions. Hence, not a better oxidizing agent than A

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1 year ago
What volume (in liters) of a solution contains 0.14 mol of KCl?
oksano4ka [1.4K]

Answer:

\boxed {\boxed {\sf 0.078 \ L }}

Explanation:

We are asked to find the volume of a solution given the moles of solute and molarity.

Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:

molarity= \frac{moles \ of \ solute}{liters \ of \ solution}

We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.

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  • liters of solution=x

Substitute these values/variables into the formula.

1.8 \ mol \ KCl/ L = \frac { 0.14 \ mol \ KCl}{x}

We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

\frac {1.8 \ mol \ KCl/L}{1} = \frac{0.14 \ mol \ KCl}{x}

1.8 \ mol \ KCl/ L *x = 1*0.14 \ mol \ KCl

1.8 \ mol \ KCl/ L *x = 0.14 \ mol \ KCl

Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.

\frac {1.8 \ mol \ KCl/ L *x}{1.8 \ mol \ KCl/L} = \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}

x= \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}

The units of moles of potassium chloride cancel.

x= \frac{0.14 }{1.8 L}

x=0.07777777778 \ L

The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.

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