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denpristay [2]
3 years ago
5

Substances A, B, and C can all act as oxidizing agents. In solution, A is green, B is yellow, and C is red. In the reactions in

which they participate, they are reduced to A-, B-, and C- ions, all of which are colorless. When a solution of C is mixed with one containing B- ions, the color changes from red to yellow.Which species is oxidized? Which is reduced?When a solution of C is mixed with one containing A- ions, the color remains red.Is C a better oxidizing agent than A?Is C a better oxidizing agent than B?
Chemistry
1 answer:
igor_vitrenko [27]3 years ago
3 0

Explanation:

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions.

Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes reduction reactions.

When oxidizing agent-A get reduced it changes green to colorless.

A+e^-\rightarrow A^-

When oxidizing agent-B get reduced it changes yellow to colorless.

B+e^-\rightarrow B^-

When oxidizing agent-C get reduced it changes red to colorless.

C+e^-\rightarrow C^-

1) When we added solution C that oxidizing agent-C in solution containing B^- ions changes from red to yellow:

C+B^-\rightarrow C^-+B(yellow)

So, in this C is oxidizing B^- ion into B which yellow in color.

C is reduced and B^- ions is oxidized.

Here, B^- are oxidized by C which means that C a better oxidizing agent than B.

2) When a solution of C is mixed with one containing A- ions, the color remains red.

C+A^-\rightarrow no reaction

As we had observed that no color change was seen on adding substance C to the solution with A^- ions which indicates that C was unable to oxidize A^- ions. Hence, not a better oxidizing agent than A

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Answer:

(a)  Cu²⁺ +2e⁻ ⇌ Cu

(c) 0.07 V  

Explanation:

(a) Cu half-reaction

Cu²⁺ + 2e⁻ ⇌ Cu

(c) Cell voltage

The standard reduction potentials for the half-reactions are+

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Cu²⁺ + 2e⁻ ⇌ Cu;                  0.34  

Hg₂Cl₂ + 2e⁻ ⇌ 2Hg + 2Cl⁻; 0.241

The equation for the cell reaction is

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Cu²⁺(0.1 mol·L⁻¹) + 2e⁻ ⇌ Cu;                               0.34  

<u>2Hg + 2Cl⁻ ⇌ Hg₂Cl₂ + 2e⁻;                             </u> <u>-0.241 </u>

Cu²⁺(0.1 mol·L⁻¹) + 2Hg + 2Cl⁻ ⇌ Cu + Hg₂Cl₂;   0.10

The concentration is not 1 mol·L⁻¹, so we must use the Nernst equation

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T = 25 + 273.15 = 298.15 K

Q = \dfrac{\text{[Cl}^{-}]^{2}}{ \text{[Cu}^{2+}]} = \dfrac{1}{0.1} = 10\\\\E = 0.10 - \left (\dfrac{8.314 \times 298.15 }{2 \times 96485}\right ) \ln(10)\\\\=0.010 -0.01285 \times 2.3 = 0.10 - 0.03 = \textbf{0.07 V}\\\text{The cell potential is }\large\boxed{\textbf{0.07 V}}

 

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3 years ago
B) Ethane has the formula C2H6. In terms of electronic structure,
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Answer:

There is one single covalent bond between two carbon atoms.

Explanation:

We know that sharing of electrons form covalent bonds.

If we look upon K,L,M ,N shells of the carbon and hydrogen atoms.

We found that Hydrogen is having only  1 electron in K shell.

And Carbon on the other hand is having 2 electrons in K shell and 4 electrons in L shell.

So carbon have  4 valence electrons,and it can share 4 bonds with any relevant atom to complete its octet.

And Hydrogen requires  1 electron to complete its doublet.

Alkane general formula C_{n}H_{2n+2}

For ethane n=2

C_{2}H_{4+2} = C_{2}H_{6}

1 Carbon atom is shared by  3 Hydrogen.

The remaining one electron (4-3)=1 of carbon will be shared with another carbon atom.

An image of the sharing of electrons attached below,

Hence we have only  1 covalent bond between the two.

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