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Vladimir [108]
2 years ago
8

What's the while compound called knowing all those lines are carbon​

Chemistry
1 answer:
Kisachek [45]2 years ago
6 0

Answer:

<u>2-chlorohexane</u>

Explanation:

<u>In this figure</u> :

  • There are 6 carbon atoms
  • The Cl atom is bonded to the 2nd carbon atom

⇒ The Cl is a substituent group, termed as -chloro

⇒ Based on IUPAC nomenclature, the 6 atom chain starts with hex

⇒ There are only single bonds present, so it is an alkane

<u>The name is</u> :

  • <u>2-chlorohexane</u>
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2. Calculate the molarity of a solution if there are 1.5 mol of NaCl in 2.3 L of solution.
rodikova [14]

Answer:

0.65 M

Explanation:

Molarity (M) is the amount of moles of a substance per liter.

In other words, M = moles of substance / liters of solution

Since you're already given the moles of NaCl and the volume of the solution, you can plug those into the equation.

M = moles of NaCl / liters of solution

M = 1.5 mol NaCl / 2.3 L

M = 0.65 mol/L (or 0.65 M)

5 0
2 years ago
Write a food chain in which the hawk is a secondary consumer:​
KATRIN_1 [288]

Answer:

Food chain - Frog ---> Snake ---> Hawk

Hope this helps!

3 0
2 years ago
Read 2 more answers
An object's mechanical energy is the sum of its
n200080 [17]
Potential energy or kinetic energy.
3 0
2 years ago
Integrated rate law for second order unimolecular irreversible
kirill115 [55]

Answer:

The rate law for second order unimolecular irreversible reaction is

\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }

Explanation:

A second order unimolecular irreversible reaction is

2A → B

Thus the rate of the reaction is

v = -\frac{1}{2}.\frac{d[A]}{dt} = k.[A]^{2}

rearranging the ecuation

-\frac{1}{2}.\frac{k}{dt} = \frac{[A]^{2}}{d[A]}

Integrating between times 0 to <em>t </em>and between the concentrations of [A]_{0} to <em>[A].</em>

\int\limits^0_t -\frac{1}{2}.\frac{k}{dt} =\int\limits^A_{0} _A\frac{[A]^{2}}{d[A]}

Solving the integral

\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }

5 0
3 years ago
How many grams of fluorine must be reacted with excess lithium iodide to produce 10.0 grams of lithium fluoride?
rewona [7]
Answer:
             7.32 g of F₂

Solution:
              The equation is as follow,

                                   2 LiI  +  F₂    →    2 LiF  +  I₂

According to equation,

           51.88 g (2 mole) of LiF is produced from  =  37.99 g (1 mole) F₂
So,
                          10 g of LiF will be produced by  =  X g of F₂

Solving for X,
                      X  =  (10 g × 37.99 g) ÷ 51.88 g

                      X  =  7.32 g of F₂
8 0
3 years ago
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