Thanks but who would like to help me with the rest ......working out for 63+9×72÷9-13
2 answers:
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Answer:
57.8125% or approx. 57.8%
Step-by-step explanation:
There is a 1/4, or 25%, or 0.25 chance that an egg has salmonella.
Thus, there is a 75%, or 0.75 chance that an egg DOESN'T contain salmonella.
Let's find the probability that all 3 of Larry's eggs are free from salmonella. Larry would have to hit that 75% chance 3 times in a row. The chance of that happening is:
0.75 * 0.75 * 0.75 = = 0.421875
From this, we can deduce that if there is a 0.421875 (42.1875%) chance that all eggs are safe to eat, there must be a...
1 - 0.421875 = 0.578125
...0.578125 (57.8125%) chance that 1 or more of Larry's eggs do have salmonella.
Answer: approx. 57.8% or 57.8125%
Answer:
$1,701.64
Step-by-step explanation:
(see attached for reference)
recall that for compound interest, the following formula applies:
A = P [1 + (r/n) ] ^ (nt), where
A = final amount (we are asked to find this)
P = Principal amount = $1,200
r = interest rate = 5% = 0.05
t = 7 years
n = 12
Substituting these into the equation,
A = 1200 [1 + (0.05/12) ] ^ [(12)(7)]
A = $1,701.64
