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lidiya [134]
3 years ago
9

Theo has 50 tea light candles. Madeline has half as many candles as Theo. How many candles does Madeline have ?

Mathematics
2 answers:
notsponge [240]3 years ago
7 0

Answer: 25

Step-by-step explanation:

Simple! Divide 50 in half, which is 25 and that's how many

salantis [7]3 years ago
4 0
<h2>Answer:</h2>

The number of candles Madeline have is:

                            25

<h2>Step-by-step explanation:</h2>

It is given that:

Theo has 50 tea light candles.

Madeline has half as many candles as Theo.

This means that the number of candles with Madeline is half the number of candles with Theo.

The number of candles with Madeline is calculated by:

                            \dfrac{50}{2}=25

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98 x 63 – 32 x 69 =
Dahasolnce [82]

Answer:

3966

Step-by-step explanation:

Use order of operations to solve this problem:

  • Parentheses
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  • Multiply (Left to right)
  • Divide (Left to right)
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  • Subraction

In your case, there are no parentheses or exponents, so we can skip right the the multiply and divide step. The first multiplication is 98*63=6174. The next step is to do 32*69=2208. Then you minus 6174-2208=3966.

Hope this helps!

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2 years ago
What is the vertex of y=1/2(x+4)^2+1
Margaret [11]

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3 years ago
The Greek letter iota, i, represents the square root of -1 (). We call i an imaginary unit. Any number that is a product of a re
Nadusha1986 [10]

Happy New Year from MrBillDoesMath!

Answer:

 i ^ (2n) = (i^2)^n = (-1)^n = -1 if n is odd and = 1 if n is even

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Not sure if this answers your question but hopefully pushes you n the right direction.


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4 0
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Find the surface area of this triangular prism. Be sure to include the correct unit in your answer.
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8 0
2 years ago
A cooler has a temperature of 32 degrees Fahrenheit. A bottled drink is placed in the cooler with an initial temperature of
FinnZ [79.3K]

Answer:

k \approx 0.44

Step-by-step explanation:

Given function:

f(t) = (ce)^{-kt}+32

As per question statement:

Initial temperature of bottle is 70 ^\circ F.

i.e. when time = 0 minutes, f(t) = 70 ^\circ F

70 = ce^{-k\times 0}+32\\\Rightarrow 38 = ce^{0}\\\Rightarrow c = 38

After t = 3, f(t) = 42^\circ F

42 = 38 \times e^{-k\times 3}+32\\\Rightarrow 42-32 = 38 \times e^{-3k} \\\Rightarrow 10  = 38 \times e^{-3k} \\\Rightarrow e^{3k} = \dfrac{38}{10}\\\Rightarrow e^{3k} = 3.8\\\\\text{Taking } log_e \text{both the sides:}\\\\\Rightarrow log_e {e^3k} = log_e {3.8}\\\Rightarrow 3k \times log_ee=log_e {3.8}   (\because log_pq^r=r \times log_pq)\\\Rightarrow 3k \times 1=log_e {3.8}\\\Rightarrow 3k = 1.34\\\Rightarrow k = \dfrac{1.34}{3}\\\Rightarrow k \approx 0.44

Hence, the value is:

k \approx 0.44

8 0
3 years ago
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