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3 years ago

Theo has 50 tea light candles. Madeline has half as many candles as Theo. How many candles does Madeline have ?

Mathematics

2 answers:

notsponge [240]3 years ago

7 0

Answer: 25

Step-by-step explanation:

Simple! Divide 50 in half, which is 25 and that's how many

salantis [7]3 years ago

4 0

<h2>Answer:</h2>

The number of candles Madeline have is:

<h2>Step-by-step explanation:</h2>

It is given that:

Theo has 50 tea light candles.

Madeline has half as many candles as Theo.

This means that the number of candles with Madeline is half the number of candles with Theo.

The number of candles with Madeline is calculated by:

$\dfrac{50}{2}=25$

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Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

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P(D|A) = Probability that someone has a disease given that he tests positive.

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So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

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So, $P(D)=\frac{1}{10000}$

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$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

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Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

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