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Paladinen [302]
2 years ago
12

There were 24 students running in a race. How many different arrangements of the first, second, and third place are possible?

Mathematics
2 answers:
krok68 [10]2 years ago
5 0

Answer:9

Step-by-step explanation:

Nadya [2.5K]2 years ago
3 0
The answer to this would be 9
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A cookie recipe calls for 2 3/4 cups of chocolate chips and 1 1/3 cup of butterscotch chips. How much is needed all together for
MArishka [77]

Answer:

4 1/12

Step-by-step explanation:

2  9/12 + 1  4/12 = 4 1/12

7 0
3 years ago
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I NEED HELP ASAP! THANKS :)
4vir4ik [10]

Answer:

Last option: increasing: -2 < x < 0 and x> 3/2;

decreasing: x < -2 and 0 < x < 3/2

Step-by-step explanation:

The function given is an absolute cubic function. (Pictured below).

We can determine from the graph that the equation increases over the interval:

increasing: -2 < x < 0 and x> 3/2;

decreasing: x < -2 and 0 < x < 3/2

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2 years ago
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(3x^2 + 8x - 4 ) -(-x^2 +5x +2) simplify​
xxMikexx [17]

Answer:

4x^2+3x-6

Step-by-step explanation:

4 0
2 years ago
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Which expression is equivalent to the following: *<br> 20x+9y
anzhelika [568]

Answer:

B. 5(4x+2y)-y

Step-by-step explanation:

Bring the 5 over and multiply

5×4 = 20 + x

=20x (thats the beginning of the expression)

5×2 = 10

10y - y = 9 because the - y is basically telling you to get rid of one of the y values so 10 - 1 = 9y

7 0
2 years ago
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 ce
julsineya [31]

Answer:

The proportion of students whose height are lower than Darnell's height is 71.57%

Step-by-step explanation:

The complete question is:

A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.

What proportion of proportion of students height are lower than Darnell's height.

Answer:

We first calculate the z-score corresponding to Darnell's height using:

Z=\frac{X-\mu}{\sigma}

We substitute x=161.4 , \mu=150, and \sigma=20 to get:

Z=\frac{161.4-150}{20} \\Z=0.57

From the normal distribution table, we read 0.5 under 7.

The corresponding area is 0.7157

Therefore the proportion of students whose height are lower than Darnell's height is 71.57%

8 0
2 years ago
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