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Kitty [74]
1 year ago
11

Which point is located at (-3, 4)?

Mathematics
1 answer:
o-na [289]1 year ago
8 0

Answer:A

Step-by-step explanation:

-3 to the left and up 4

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What is the factored form of x2 - 4x - 5?
Kazeer [188]

Answer:

Option D, (x - 5)(x + 1)

Step-by-step explanation:

<u>Step 1:  Factor </u>

x^2 - 4x - 5

x^2 - 5x + x - 5

(x - 5)(x + 1)

Answer:  Option D, (x - 5)(x + 1)

6 0
3 years ago
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PLEASE HELP WILL GIVE BRAINLIEST, THANKS, AND STARS.
Jlenok [28]

The median is the halfway point,

Arrange the numbers in a line from smallest to largest:

01, 03, 14, 15 , 22, 35, 35, 43

There are 8 numbers.

When there is an even amount of numbers, find the middle two numbers, add them together and divide by 2.

15 + 22 = 37 /2 = 18.5

The median is 18.5

7 0
3 years ago
What is the area of this figure. <br><br><br> 128 in<br> 136 in<br> 153 in<br> 258 in
aliya0001 [1]
So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
6 0
3 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
Please hurry I need help
RSB [31]

Answer:

48f^2-110f+63

Step-by-step explanation:

We multiple every part of first sum with every prt of the 2nd sum:

(6f-7)(8f-9)=48f^2-54f-56f+63=

48f^2-110f+63

5 0
2 years ago
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