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Nata [24]
3 years ago
7

A line and two points are guaranteed to be coplanar if

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0
The points lie on the line, I believe, since they're part of it. 
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If the difference (3x2 - 2x + 5) – (x2 + 3x - 2) is multiplied by 1/2x^2,
Mars2501 [29]
Answer in photo below
4x^4-10x^3+14x^2

6 0
3 years ago
Dividing integers
telo118 [61]

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.</em>

here,

7. (-154) ➗ (-14) =11

11. (-40) ➗10=-4

15. 90 ➗ (-15)=-6

16. 108 ➗ (-9)=-12

17. (-48) ➗ (-6)=8

18. (-105) ➗ 7=-15

hope it helps you..........

8 0
3 years ago
The area of a rectangle is 12.65 m^2. the length measures 5.5 m. what is the width of the rectangle?
Nat2105 [25]

Answer:

The width of the rectangle is 2.3 m

Step-by-step explanation:

Now, when we are asked to find the area of the rectangle, we will use the formula: Area= length * width. We should be given with at least two values, and then we can use the above formula and can find the third variable.

Now, we are given that the area of a rectangle is 12.65 m^2 and the length measures 5.5 m

So the width is given as:

Area= length * width\\\Rightarrow 12.56= 5.5 * width\\\Rightarrow width= \frac{12.56}{5.5}\\\Rightarrow width=2.3 ~m

So this is the required with of the rectangle.

4 0
4 years ago
Read 2 more answers
Mr. Jones charged Roberta $32 for parts and $15 per hour for labor to repair her
Galina-37 [17]

Answer:

2.

Step-by-step explanation:

Since 3 hours and $15 an hour

5 0
3 years ago
Please help me <br><br>If 180°&lt;α&lt;270°, cos⁡ α=−8/17, what is sin -α?
rewona [7]

Starting from the fundamental trigonometric equation, we have

\cos^2(\alpha)+\sin^2(\alpha)=1 \iff \sin(\alpha)=\pm\sqrt{1-\cos^2(\alpha)}

Since 180, we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have

\sin(\alpha)=-\sqrt{1-\cos^2(\alpha)}

Plugging the numbers, we have

\sin(\alpha)=-\sqrt{1-\dfrac{64}{289}}=-\sqrt{\dfrac{225}{289}}=-\dfrac{15}{17}

Now, just recall that

\sin(-\alpha)=-\sin(\alpha)

to deduce

\sin(-\alpha)=-\sin(\alpha)=-\left(-\dfrac{15}{17}\right)=\dfrac{15}{17}

6 0
3 years ago
Read 2 more answers
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