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3 years ago

A line and two points are guaranteed to be coplanar if

Mathematics

1 answer:

kicyunya [14]3 years ago

5 0

The points lie on the line, I believe, since they're part of it.

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PLEASE ANSWER I WILL MARK AS BRAINLIEST

Tomtit [17]

Answer:

Six

Step-by-step explanation:

1.Convert all volumes to millilitres

(a) Chlorpheniramine

V = 100 mL

(b) Lidocaine

$V = \text{2 fl oz} \times \dfrac{\text{29.57 mL}}{\text{1 fl oz}} = \textbf{59 mL}$

(c) Banana flavouring

$V = \dfrac{1}{2}\text{ tsp} \times \dfrac{\text{4.928 mL}}{\text{1 tsp}} = \textbf{2.5 mL }$

2. Calculate the total volume

Chlorpheniramine = 100 mL

Lidocaine = 59

Banana flavouring = <u> 2.5 </u>

TOTAL = 162 mL

3. Calculate the number of doses

$\text{Doses} = \text{162 mL} \times \dfrac{\text{1 dose}}{\text{10 mL}} = \text{16.2 doses}\\\\\text{You can't take a fraction of a dose, so the there are $\large \boxed{\textbf{16 doses}}$}$

5 0

2 years ago

Free points u guys can have them

sertanlavr [38]

Hi thank u vvv much i am currently failing my bio class and in need of help

7 0

3 years ago

Read 2 more answers

Answer? BRAINLIEST IF CORRECT

alexira [117]

The answer is 12 your welcome

4 0

2 years ago

Eighty percent of what number is 1120

algol [13]

Answer:

1140

Step-by-step explanation:

6 0

3 years ago

The mean per capita income is 20,90820,908 dollars per annum with a standard deviation of 407407 dollars per annum. What is the

LiRa [457]

Answer:

$z=\frac{20880-20908}{\frac{407}{\sqrt{55}}}= -0.51$

$z=\frac{20936-20908}{\frac{407}{\sqrt{55}}}= 0.51$

Then we can find the probability of interest with this difference:

$P(-0.51$

And using the normal standard distribution or excel we got:

$P(-0.51$

So then the probability that the sample mean would differ from the true mean by less than 28 dollars from the sample of 55 is approximately 0.390

Step-by-step explanation:

We define the variable of interest as the per capita income and we know the following properties for this variable:

$\mu=20908$ and $\sigma=407$

We want to find this probability:

$P(20908-28$

We select a sample size of n=55 and we define the z score formula given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

We can find the z score then for 20880 and 20936 and we got:

$z=\frac{20880-20908}{\frac{407}{\sqrt{55}}}= -0.51$

$z=\frac{20936-20908}{\frac{407}{\sqrt{55}}}= 0.51$

Then we can find the probability of interest with this difference:

$P(-0.51$

And using the normal standard distribution or excel we got:

$P(-0.51$

So then the probability that the sample mean would differ from the true mean by less than 28 dollars from the sample of 55 is approximately 0.390

7 0

2 years ago