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mel-nik [20]
3 years ago
6

If x can be any integer what is the greatest possible value of 1^x - |x|

Mathematics
1 answer:
natali 33 [55]3 years ago
4 0
x=1 
Is dat what u want? If not tell me and I'll help u 


Hope this helped :)
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Fantom [35]
The distance is 4.24 units
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A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult
klio [65]

Answer:

<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>

Step-by-step explanation:

Probability = \frac{Required outcomes}{Total possible outcomes}

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

<em>Total possible outcomes: 20</em>


<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = \frac{n(Odd)}{Total} = \frac{10}{20} = \frac{1}{2} = 0.5


Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = \frac{n(5)}{Total} = \frac{4}{20} = \frac{1}{5} = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = \frac{2}{20}=\frac{1}{10}=0.1

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6

7 0
3 years ago
The odds against Carl beating his friend in a round of golf are 9:7. Find the probability that Carl will lose?
grandymaker [24]

The ratio 9:7 gives you following statement:

  • Carl will win in 9 cases from 9+7=16;
  • Carl will lose in 7 cases from 16.

Then the probability that Carl will lose is

Pr(\text{Carl will lose})=\dfrac{7}{16}.

Answer: Pr(\text{Carl will lose})=\dfrac{7}{16}.


7 0
3 years ago
What is the equivalent expression of 8x+7y+5x+4y+2y
Natalija [7]

Answer:

13x+13y

Step-by-step explanation:

(combine like terms)

8x+5x=13x

7y+4y+2y=13y

hope this helped you!

4 0
3 years ago
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