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Romashka-Z-Leto [24]
4 years ago
8

If the diameter of a circle has endpoints A (7,2) and B (-1,8), where is the center?

Mathematics
2 answers:
Elenna [48]4 years ago
6 0
<span>first we will get sum of X coordinates of A and B
secondly we will divide it by two
same sum the Y coordinates and divide it by
(-1+7)/2=3 and  (2+8)/2=5
so the center will be (3,5)
hope it helps
</span>
docker41 [41]4 years ago
3 0
In the middle: x-coordinate= {7-(-1)}/2= 4 y-coordinate= (8-2)/2= 3 So centre is (4,3)
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wolverine [178]

Answer for the first box:  20

Answer for the second box: 6

====================================================

Explanation:

The notation a(1) represents the first term of the sequence given. The first term is 20, so thats why a(1) = 20.

The notation a(n) = a(n-1) + ____ means we add some term to the previous term to get the next. This process happens over and over. In this case, we add 6 to each term to get the next

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  • term4 = term3 + 6 = 32 + 6 = 38

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So we write a(n) = a(n-1) + 6

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\begin{cases}a(1) = 20\\a(n) = a(n-1) + 6\end{cases}

-------------------------

Extra info:

The common difference is d = 6 and the first term is a = 20

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