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Romashka-Z-Leto [24]
3 years ago
8

If the diameter of a circle has endpoints A (7,2) and B (-1,8), where is the center?

Mathematics
2 answers:
Elenna [48]3 years ago
6 0
<span>first we will get sum of X coordinates of A and B
secondly we will divide it by two
same sum the Y coordinates and divide it by
(-1+7)/2=3 and  (2+8)/2=5
so the center will be (3,5)
hope it helps
</span>
docker41 [41]3 years ago
3 0
In the middle: x-coordinate= {7-(-1)}/2= 4 y-coordinate= (8-2)/2= 3 So centre is (4,3)
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Paladinen [302]

Answer <u>(assuming it is allowed to be in point-slope format)</u>:

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Step-by-step explanation:

1) First, determine the slope. We know it has to be perpendicular to the given equation, y = -\frac{3}{2} x-4. That equation is already in slope-intercept form, or y = mx + b format, in which m represents the slope. Since -\frac{3}{2} is in place of the m in the equation, that must be the slope of the given line.

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y-4 = \frac{2}{3}(x-1)

3 0
3 years ago
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