Answer:
x just represents a number
Answer:73. 0
Step-by-step explanation:
Radius=8.02
Tita =130
Area of sector = tita/360 x πr^2
130/360 x 22/7 x (8.02) ^2
130/360 x 22/7 x64. 3204
= 72.99
To the nearest tenth = 73.0
If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of <span>x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
b^2-4(1)(16) ≥ 0
</span><span>b^2-64 ≥ 0
(b+8)(b-8) </span><span>≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where </span>(b+8)(b-8) is positive.
X= 25
Explanation:
The two lines are equal. Since 48+16= 64,
the other line has to equal 64 as well.
64-39= 25
Answer:
The number of original students desks were there in school before purchase was made is 980 .
Step-by-step explanation:
Given as :
The total number of new desks purchased including teacher and students = 295
The number of new desks purchased for students = 
of original students desks available
The number of new desks purchased for teachers = 50
Let The number of original students desks available before purchase = S
Now, According to question
∵ The total number of new desks purchased including teacher and students = 295
I.e The number of new desks purchased for students + The number of new desks purchased for teachers = 295
Or, of S + 50 = 295
Or, × S = 295 - 50
Or , × S = 245
∴ S = 245 × 4 = 980
So, original desks available for students = S = 980
Hence The number of original students desks were there in school before purchase was made is 980 . Answer
