12, 18 , 24, 30, 36, 42….
1/sin^2x-1/tan^2x=
1/sin^2x-1/ (sin^2x/cos^2x)<<sin tan= sin/cos>>
= 1/sin^2x- cos^2x / sin^2x
= (1- cos^2x) / sin^2x <<combining into a single fraction>>
sin^2 x / sin^2x <<since 1- cos^2 x sin^2 x
=1
this simplifies to 1.
Divide 10 each time.
300/10=30
30/10=3
3/10=0.3
0.3/10=0.03
0.03/10=0.003
etc.
<span>2x + x = 12
=> x =12/3 =4
so, original number is 84. </span>
Answer:
// C++ Program to arithmetic operationf on 2 Numbers using Recursion
// Comments are used for explanatory purpose
#include <bits/stdc++.h>
using namespace std;
// add10 recursive function to perform arithmetic operations
int add10(int m, int n)
{
return (m + product(n, 10)); //Result of m + n * 10
return 0;
}
// Main Methods Starts here
int main()
{
int m, n; // 2 Variables m and n declared as integer
cin>>m; // accept input for m
cin>>n; // accept input for n
cout << "Result : "<<add10(m,n); // Print results which is calculated by m + 10 * n
return 0;
}
