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3 years ago

Paul has a standard deck of cards. what is the probability he will choose a 2?

Mathematics

1 answer:

Zigmanuir [339]3 years ago

6 0

$|\Omega|=52\\
|A|=4\\\\
P(A)=\dfrac{4}{52}=\dfrac{1}{13}\approx7,7\%$

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Write the point-slope form of the equation of the line through the given point with the given slope. (-5,0) slope= 2/3

amid [387]

Answer:

Step-by-step explanation:

y - 0 = 2/3(x + 5)

y = 2/3x + 10/3

8 0

3 years ago

PLEASE HELP I POSTED LIKE 2 HOURS AGO WITH THIS QUESTION AND I NEED HELP:)

garik1379 [7]

A system is inconsistent when there are no solutions between the two equations. Graphically, the lines will be parallel (they never meet!) and the slopes will be the same. But the y-intercepts will be different.

Let's look at the four equations, with each solved as needed, into y = mx + b form.

A: 2x + y = 5

y = 5 - 2x

y = -2x + 5

Compared to y = 2x + 5, the slopes are different, so this system won't be inconsistent. Not a good choice.

B: y = 2x + 5

Compared to y = 2x + 5, the slopes are the same and the y intercepts are the same. This system has infinitely many solutions. Not a good choice.

C: 2x - 4y = 10

-4y = 10 - 2x

-4y = -2x + 10

y = 2/4x -10/4

Here the slopes are different, so, like A this is not a good choice.

D: 2y - 4x = -10

2y = =10 + 4x

2y = 4x - 10

y = 2x - 5

Compared to y = 2x + 5 we have the same slopes and different y intercepts. The lines will be parallel and the system is inconsistent.

Thus, D is the best choice.

7 0

3 years ago

Read 2 more answers

It's the day before Valentine's Day and Shelly needs to get Valentine cards for all of her classmates.The desks are arranged in

Vitek1552 [10]

Answer:

Step-by-step explanation:

No of desks along length of the rectangle = 7 as it is 7 rows wide.

No of desks along breadth of the rectangle = 7 as it is 5 rows long.

Total number of students is product of these two numbers.

So number of students = 35.

But three desks are empty.

Total students = 35- 3

= 32.

4 0

3 years ago

The formula for the area of a trapezoid with altitude k and bases m and n is . A=k/2 (m+n) solve for m..

SashulF [63]

Answer:

$m=A\times\frac{2}{k}-n$

Step-by-step explanation:

Given : The formula for the area of a trapezoid with altitude k and bases m and n is $A=\frac{k}{2}(m+n)$

We have solve for m .

Consider the given formula $A=\frac{k}{2}(m+n)$

Multiply both side by $\frac{2}{k}$ , we have,

$A\times\frac{2}{k}=m+n$

Now subtract n both side, we have,

$A\times\frac{2}{k}-n=m$

Thus, $m=A\times\frac{2}{k}-n$

5 0

3 years ago

Read 2 more answers

I don’t get this :(

muminat

Ok so for the first one it’s super simple I’m gonna do it as less complicated so it can help you :)

So first we need to convert the mixed number to an improper fraction

1 4/5 = 9/5

Now we need to reduce the numbers greatest common divisor which is 3

3/5 x 6

Now multiply the numbers

Your answer is 18/5 I hoped this help

Now for the second one

this one is a little more complicated and I don’t know how to make it sound easier so I’m gonna tell you the answer which is 580/21

The last one is the same steps we did for the first one which is 27/20

I hoped this helped you it is a little difficult but you’ll get the hang of it :)

5 0

3 years ago