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boyakko [2]
4 years ago
10

34 ÷ [(7.2 × 0.8) 3.24]

Mathematics
1 answer:
kvv77 [185]4 years ago
6 0
Answer: 9
because you need to first use the ones in the parentheses and then move on.
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If two angles are both vertical and supplementary, can we determine the angles? Is it possible to be both vertical and complemen
Mars2501 [29]

Answer:

Two angles can be vertical and supplementary only if they add up to 90 degrees because there perpendicular.

Step-by-step explanation:

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3 years ago
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What are some smaller branched tubes that connect the arteries abd viens called.
Nadusha1986 [10]
I’m pretty sure the answer is capillaries from biology last year!
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3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3


has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
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What's the answer please I need help w×wwwwww
Leona [35]
3\leqx

You can put that on a number line.  Be sure that the dot you use is closed.
3 0
3 years ago
If sin θ = 7 over 25, use the Pythagorean Identity to find cos θ. cos θ = ± 17 over 24 cos θ = ± 17 over 25 cos θ = ± 24 over 25
elena-s [515]
\sin^2\theta+\cos^2\theta=1

\implies\cos^2\theta=1-\left(\dfrac7{25}\right)^2=\dfrac{576}{625}\implies\cos\theta=\pm\dfrac{24}{25}
6 0
3 years ago
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