Answer:
14.1
Step-by-step explanation:
Answer:
l = 23 cm and w = 5.7 cm
Step-by-step explanation:
Perimeter = twice the length plus twice the width
let w = width
let l = length
l = 5.9 + 3w
57.4 = 2(5.9 + 3w) + 2w
57.4 = 11.8 + 6w + 2w
57.4 = 11.8 + 8w
45.6 = 8w
w = 5.7
Substitute 5.7 for 'w' to get 'l':
l = 5.9 + 3(5.7)
l = 23
Answer:
0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 170cm and standard deviation of 7.5 cm.
This means that 
Find the probability that a randomly selected male has a height > 180 cm.
This is 1 subtracted by the pvalue of Z when X = 180. So



has a pvalue of 0.9082
1 - 0.9082 = 0.0918
0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.
Step-by-step explanation:
∠4 = ∠1 & ∠2 = ∠3
360 - 2(98) = ∠2 + ∠3
∠3 = 164/2
∠3 = 82°