Answer:
Equation I , II and V.
Step-by-step explanation:
Number II:L
0.5(8x + 4) = 4x + 2 Distributing the 0.5 over the parentheses:
4x + 2 = 4x + 2
The 2 sides of this equation are identical so we can make x any value to fit this identity. That is there are Infinite Solutions.
I and V are also included:
I: 12x + 24 = 12x + 24.
V left side = right side.
For either square root to exist, you require that
. This is true for all
, since
is always non-negative. This means the domain of
as a function of
is all real numbers, or
or
.
Now, because
is non-negative, and the smallest value it can take on is 7, it follows that the minimum value for the positive square root must be
, while the maximum value of the negative root must be
. This means the range is
, or
, or
![(-\infty,-\sqrt7]\cup[\sqrt7,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-%5Csqrt7%5D%5Ccup%5B%5Csqrt7%2C%5Cinfty%29)
.
Equation 1) y = x² + 10x + 11
Equation 2) y = x² + x - 7
Subtract equations from one another.
9x = 18
Divide both sides by 9.
x = 2
Plug in 2 for x in the first equation.
y = x² + 10x + 11
y = 2² + 10(2) + 11
Simplify.
y = 4 + 20 + 11
y = 35
Plug in 35 for y and 2 for x in the first equation to check your work.
y = x² + 10x + 11
35 = 2² + 10(2) + 11
35 = 4 + 20 + 11
35 = 24 + 11
35 = 35
So, we know that our answer is correct! :))
x = 2, y = 35
Answer:
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Step-by-step explanation:
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