Answer: (4, 8)
Step-by-step explanation:
(4,8)
Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So






Rounding up
We need a sample size of 564.
Answer:
b
Step-by-step explanation:
cuz I said so also show me your cake
Answer:
Sorry ineed point ehhh thnks po sa points:)
At a certain company, 64.5% of the employees have engineering degrees.
To express the percentage as a decimal we need to remove the % symbol.
To remove % symbol we always divide by 100
When we divide by 100 we move the decimal point two places to the left.

The decimal vale of 64.5% is 0.645