V^2 = u^2 - 2gh; where v is the final speed, u is the initial speed, g = 9.8 m/s = 0.54 ft/min is the accerelation due to gravity, h = height.
At the maximum height, the final speed is 0.
u^2 = 2gh = 2 x 0.54 x 36 = 38.58
u = sqrt(38.58) = 6.21 ft/min
Therefore, the stne should be thrown with 6.21 ft/min
Answer:
42
Step-by-step explanation:
According to ACT WorkKeys Curriculum.
Answer:
12 points
Step-by-step explanation:
9 is 1.5 times 6, so 8 times 1.5 gives you the answer of 12 points.
Note that rotation will not affect the shape and size of an object.
Rotation with respect to a point preserves the corresponding sides and the corresponding angles of the original image.
Hence, the statements
The corresponding angle measurements in each triangle between the pre-image and the image are preserved and
The corresponding lengths, from the point of rotation, between the pre-image and the image are preserved
are true.
