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meriva
4 years ago
6

Two rhombuses with the same side lengths are always congruent ?

Mathematics
1 answer:
lyudmila [28]4 years ago
8 0

Answer:

False

Step-by-step explanation:

A rhombus is a quadrilateral with

1. all side length equal

2. opposite side parallel

3. opposite angles are congruent.

______________________________________

If there are two rhombus with same side length ,

conditions so that they must be always congruent.

1. Side length must be equal

2. corresponding angles to equal sides must also be equal.

It is possible that the sides of two rhombus will be same

but their angles can differ and hence the two rhombus may or may not be congruent.

Thus,

Two rhombuses with the same side lengths are always congruent

given statement is false

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The cost of making a cheese cake is RM45. In
mars1129 [50]

Answer:

CHEESE

Step-by-step explanation:

SKDMALSD

3 0
3 years ago
Need help with this problem, it's got me stuck PLZ
faust18 [17]

24x^2 +25x - 47                     53

----------------------- = -8x -3 - ---------------

ax-2                                     ax-2

add 53/ax-2 to each side

24x^2 +25x - 47+53                    

-----------------------         = -8x -3

ax-2                                    

24x^2 +25x +6                  

-----------------------         = -8x -3

ax-2      

multiply each side by ax-2

24x^2 +25x +6   = (ax-2) (-8x-3)

multiply out the right hand side

24x^2 +25x +6  = -8ax^2 +16x-3ax +6

24 = -8a      25 = 16 -3a

a = -3          9 = -3a

                   a = -3


Choice B

6 0
3 years ago
An instrument is NOT defective when: A holder is on notice that an instrument is defective when the holder: Julian receives a pr
saw5 [17]

Answer:

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Step-by-step explanation:

3 0
4 years ago
Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work
Solnce55 [7]

Answer:  

1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x    for   0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

    = 18x - 144 + 96

    = 18x - 48           for 9 ≤ x ≤ 24

The daily wage where x represents the number of hours worked can be displayed in function format as follows:

f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

       = 384

D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

6 0
3 years ago
Factor completely x2 − 10x + 25.
earnstyle [38]
X^2-10x+25 = (x-5)^2 or (x-5)(x-5)
7 0
3 years ago
Read 2 more answers
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