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3 years ago

6

Two rhombuses with the same side lengths are always congruent ?

1 answer:

lyudmila [28]3 years ago

8 0

Answer:

False

Step-by-step explanation:

A rhombus is a quadrilateral with

1. all side length equal

2. opposite side parallel

3. opposite angles are congruent.

______________________________________

If there are two rhombus with same side length ,

conditions so that they must be always congruent.

1. Side length must be equal

2. corresponding angles to equal sides must also be equal.

It is possible that the sides of two rhombus will be same

but their angles can differ and hence the two rhombus may or may not be congruent.

Thus,

Two rhombuses with the same side lengths are always congruent

given statement is false

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Step-by-step explanation:

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3 years ago

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dlinn [17]

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3 years ago

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What is the explicit rule for this geometric sequence? 4,45,425,4125,…

gregori [183]

You did not write the question correctly but I will try to answer the question according to 2 possible interpretations of your question.

Case 1:

Given the geometric sequence:

$4,\ \frac{4}{5} ,\ \frac{4}{25} ,\ \frac{4}{125} ,\ .\ .\ .$

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The explicit rule of a geometric sequence is given by $T_n=ar^{n-1}$

Therefore, the explicit rule of the given sequence is $T_n=4\left( \frac{1}{5} \right)^{n-1}\ or\ 20\left( \frac{1}{5} \right)^n$

Case 2:

Given the geometric sequence:

$4,\ 4\cdot5,\ 4\cdot25,\ 4\cdot125,\ .\ .\ .$

Common ratio is given by $r= \frac{2nd\ term}{1st\ term} = \frac{4\cdot5}{4} = 5$

The explicit rule of a geometric sequence is given by $T_n=ar^{n-1}$

Therefore, the explicit rule of the given sequence is $T_n=4(5)^{n-1}\ or\ \frac{4}{5}(5)^n$

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Answer:

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Step-by-step explanation:

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3 years ago