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azamat
3 years ago
5

7 7/8 + 2 1/3 = x this is a problem tht I’m struggling with

Mathematics
2 answers:
hichkok12 [17]3 years ago
7 0
X =
First, before we can add, we have to find a common denominator.
We can use 24.
7 7/8 x 3/3 = 7 21/24
2 1/3 x 8/8 = 2 8/24
Now we add.
7 21/24 + 2 8/24 = 9 29/24 (denominator stays the same)
Lastly, simplify
9 29/24 = 10 5/24
Hope this helps
VMariaS [17]3 years ago
6 0

Let's solve your equation step-by-step

7 7/8 +2 1/3 =x

Step 1: Simplify both sides of the equation

245/24 =x

Step 2:Flip the equation

x=245/24

Answer: x=10 5/24

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3 years ago
33) What value for x makes this equation true? 4x + 3 = 23
Tju [1.3M]

Answer:

x = 5

Step-by-step explanation:

4x + 3 = 23

Subtract 3 from both sides;

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3 0
3 years ago
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Please answer CORRECTLY !!!!!! WILL MARK BRAINLIEST !!!
Feliz [49]

Answer:

5m

and

-8n

Step-by-step explanation:

7m - 2m = 5m

and

-5n - 3n = -8n

Have a great day

7 0
3 years ago
if an amount of $5,000 is deposited into a savings account at an annual interest rate of 5%, compounded monthly, what is the val
Ugo [173]

Answer:

$8,240

Step-by-step explanation:

We are given that,

Principle amount in the savings account, P = $5,000.

Rate of interest, r = 5% = 0.05

Time period, t = 10

Also, the interest is compounded monthly, n = 12

As, we now that the value of the investment is given by P(1+\frac{r}{n})^{nt}

Thus, we have,

Investment Value = 5000(1+\frac{0.05}{12})^{12\times 10}

i.e. Investment Value = 5000(1+\frac{0.05}{12})^{12\times 10}

i.e. Investment Value = 5000(1+0.00417)^{120}

i.e. Investment Value = 5000\times 1.648

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5 0
3 years ago
JKLM is a rhombus. KM is 10 and JL is 24. Find the perimeter of the rhombus.
Ahat [919]
Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units

5 0
3 years ago
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