Answer:
x-3x^3
Step-by-step explanation:
^ means to the power of btw
Answer:
2
Step-by-step explanation:
you add 1 to 1 and that gives you 2
Answer:
The area of the sector is 17/2 π
Step-by-step explanation:
pi = π
To solve this problem we first have to find the fraction that corresponds to this angle of the total, for this we must divide the angle that they give us by 2π radians, since that is the angle of a circle
(17π/9 rad) / (2π rad) = 17/18
Now we multiply the area of the circle by this fraction and we will obtain the area of the sector that we want
9π * 17/18 = 17/2 π
The area of the sector is 17/2 π
Let x be the value of the third term.
Since it's a geometric sequence, then:
Third term/Second term = Fourth term/Third term
x/20 = 11.25/x
Cross multiplication:
x^2 = 225
x = 15
So since the ratio is constant, then it is
x/20 = 15/20 = 3/4
So the common ratio is 3/4 or 0.75.
Basic properties that will be used:

![x^{1/n}=\sqrt[n]x](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%3D%5Csqrt%5Bn%5Dx)

All of these expression can be written to match on or more of the patterns above.
![19.\quad\log_5\sqrt[4]{25}=\log_5(5^2)^{1/4}=\dfrac14\log_55^2=\dfrac12\log_55=\dfrac12](https://tex.z-dn.net/?f=19.%5Cquad%5Clog_5%5Csqrt%5B4%5D%7B25%7D%3D%5Clog_5%285%5E2%29%5E%7B1%2F4%7D%3D%5Cdfrac14%5Clog_55%5E2%3D%5Cdfrac12%5Clog_55%3D%5Cdfrac12)



![27.\quad\log_3\sqrt[6]{243}=\log_3(3^5)^{1/6}=\dfrac16\log_33^5=\dfrac56\log_33=\dfrac56](https://tex.z-dn.net/?f=27.%5Cquad%5Clog_3%5Csqrt%5B6%5D%7B243%7D%3D%5Clog_3%283%5E5%29%5E%7B1%2F6%7D%3D%5Cdfrac16%5Clog_33%5E5%3D%5Cdfrac56%5Clog_33%3D%5Cdfrac56)