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3 years ago

What is an equivalent expression for the square root of x+3?

Mathematics

1 answer:

jek_recluse [69]3 years ago

7 0

Answer:

uoub

Step-by-step explanation:

I don't think you would have any more questions than you think you might think of me

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Show 1 1/4 on a number line out of 4

sammy [17]

It’ll be on the one then there’s 3 dashes in between the 1 and 2 then you’ll mark a thick line on the little dash after the 1:)

5 0

3 years ago

3√x -2/x^2<br><br>please show step by step of differentiation before combining the terms.

EastWind [94]

Answer:

Step-by-step explanation:

Before we differentiate, let us assign a variable to the function. Let y be equal to the function i.e let y = 3√x -2/x²

In differentiation if $y = ax^{n}$ , then $\frac{dy}{dx} = nax^{n-1}$ where n is a constant and dy/dx means we are differentiating the function y with respect to x.

Applying the formula o the question given;

$y= 3\sqrt{x} -2/x^2\\y = 3{x}^\frac{1}{2} - 2x^{-2} \\\\$

On differentiating the resulting function;

$\frac{dy}{dx} = \frac{1}{2}*3x^{\frac{1}{2}-1 } - (-2)x^{-2-1} \\\\\frac{dy}{dx} = \frac{1}{2}*3x^{-\frac{1}{2}} + 2x^{-3}\\ \\\frac{dy}{dx} = \frac{1}{2}*{\frac{3}{x^{\frac{1}{2} } }} + \frac{2}{x^{3} } \\\\\frac{dy}{dx} = {\frac{3}{2x^{\frac{1}{2} } }} + \frac{2}{x^{3} }\\\\\frac{dy}{dx} = {\frac{3}{2\sqrt{x} }} + \frac{2}{x^{3} }$

To combine the terms, we will add up by finding their LCM.

$\frac{dy}{dx} = {\frac{3}{2\sqrt{x} }} + \frac{2}{x^{3} }\\\frac{dy}{dx} = \frac{3x^3+4\sqrt{x} }{2x^{3} \sqrt{x}}$

3 0

4 years ago

Larry used a pattern of colors to make a cube train. He used a red cube, a blue cube, a red cube, and another red cube before he

OlgaM077 [116]

I think 18 red cubes.
Explanation: A cube has 6 sides, so you would use the pattern 6 times. There are 3 red cubes in each pattern, you use the pattern 6 times, meaning 3 × 6, so the cube train has 18 red cubes. I hope this helps!

8 0

3 years ago

Pls answer ty if u do, u get something good!!

sergejj [24]

Answer:

In order from left to right: 3.5, 3, 60, 70

8 0

3 years ago

The figures show the dimensions of a tennis court and a basketball court given in terms of the width in feet of the tennis court

Sholpan [36]

Answer:

a. Perimeter of the tennis court = 6x + 12

Perimeter of the Basketball court = 7x + 36

b. x + 24

c. Length of the tennis court = 78 feet

Width of the tennis court = 36 feet

Length of the Basketball court = 94 feet

Width of the Basketball court = 50 feet

Step-by-step explanation:

a. Perimeter of the rectangle = 2(length + width)

So, perimeter of the tennis court = 2[(2x + 6) + x]

= 2(3x + 6)

= 6x + 12

Perimeter of the Basketball court = 2[(3x - 14)+( $\frac{1}{2}$ x + 32)]

= 6x - 28 + x + 64

= 7x + 36

b. Perimeter of the Basketball court - perimeter of the tennis court

= (7x + 36) - (6x + 12)

= 7x + 36 - 6x - 12

= x + 24

So, perimeter of the basketball court is x + 24 feet greater than that of the tennis court

c. It is given that the width of the tennis court = 36 feet

But, from the figure,

width of the tennis court = x

So, x = 36

Therefore, length of the tennis court = 2x + 6

= 2(36) + 6

= 72 + 6

= 78 feet

Width of the tennis court = x = 36 feet

Length of the basketball court = 3x - 14

= 3(36) - 14

= 108 - 14

= 94 feet

Width of the basketball court = $\frac{1}{2} x+32$

$=\frac{1}{2} (36)+32$

= 18 + 32

= 50 feet

7 0

4 years ago