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3 years ago

find the length of the second base of a trapezoid with one base measuring 29ft a height of 9ft and an area of 193.5ft

1 answer:

5 0

$\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=29\\ h=9\\ A=193.5 \end{cases}\implies 193.5=\cfrac{9(29+b)}{2} \\\\\\ 387=9(29+b)\implies \cfrac{387}{9}=29+b\implies 43=29+b\implies 14=b$

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BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

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2 years ago

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Marina86 [1]

1) Let's solve for x, writing this equation.

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1 year ago

1/2x-2/3>3 enter your answer using interval notation

Nata [24]

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3 years ago

Please Help I Don't Understand!

asambeis [7]

Answer:

5.3

Step-by-step explanation:

Since they are similar triangles, we assume the ratio between AM/AN is equal to the ratio between MB/NC.
AM/AN = 6/8 = 3/4
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1 year ago

A sample of small bottles and their contents has the following weights (in grams): 4, 2, 5, 4, 5, 2, and 6. What is the sample v

Inessa05 [86]

Answer:

What is the sample variance of bottle weight 2.33

Step-by-step explanation:

First find the mean. The mean of the bottle weight is obtained by taking the ratio of the sum of ages and total number of ages.

Mean = (4+2+5+4+5+2+6) / 7

= 28 / 7

= 4

Sample Variance = $\frac{\left[\begin{array}{ccc}(4-4)^{2} +(2-4)^{2} +\\(5-4)^{2} + (4-4)^{2} +\\(5-4)^{2} + (2-4)^{2} +\\(6-4)^{2}\end{array}\right]}{7-1}$

= $\frac{0+4+1+0+1+4+4}{6}$

= 2.33

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3 years ago