Question

find the length of the second base of a trapezoid with one base measuring 29ft a height of 9ft and an area of 193.5ft

Answer 1

$\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=29\\ h=9\\ A=193.5 \end{cases}\implies 193.5=\cfrac{9(29+b)}{2} \\\\\\ 387=9(29+b)\implies \cfrac{387}{9}=29+b\implies 43=29+b\implies 14=b$