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3 years ago

find the length of the second base of a trapezoid with one base measuring 29ft a height of 9ft and an area of 193.5ft

1 answer:

5 0

$\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=29\\ h=9\\ A=193.5 \end{cases}\implies 193.5=\cfrac{9(29+b)}{2} \\\\\\ 387=9(29+b)\implies \cfrac{387}{9}=29+b\implies 43=29+b\implies 14=b$

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Sveta_85 [38]

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Anton [14]

Answer:

B. $y = -\frac{3}{10}x + \frac{1}{2}$

Step-by-step explanation:

Well slope-intercept form is $y = ax + b$ .

Let's start with the slope.

In this case, finding the slope is easy.

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So we can cross out D.

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