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3 years ago

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Martin decided to buy 2 bags of grapes weighing 5 and two-thirds pounds each, instead of the 3 bags weighing 4 and one-fifth pou

nds each, because the bigger bags were on sale. Did he end up with more grapes or less grapes by buying the bigger bags? He ended up with about One-half pound less grapes. He ended up with about One-half pound more grapes. He ended up with about 1 pound less grapes. He ended up with about 1 pound more grapes.

2 answers:

Wewaii [24]3 years ago

5 0

Answer:

what he said is right

Step-by-step explanation:

Juli2301 [7.4K]3 years ago

3 0

Answer: He ended up with about 1 pound less grapes

Step-by-step explanation:

2 bags of grapes weighing 5 and two-thirds pounds each will give a total weight of:

= 2 × 5 2/3

= 2 × 17/3

= 34/3

= 11 1/3 pounds

3 bags weighing 4 and one-fifth pounds each, will give a weight of:

= 3 × 4 1/5

= 3 × 21/5

= 63/5

= 12 3/5

He ended up buying lesser grapes. This was about 12 3/5 - 11 1/3 = 1 4/15 less. This means that he ended up with about 1 pound less grapes

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tangare [24]

Answer:

394.9 cm

Step-by-step explanation:

The formula for a cone's surface area is A = π r ( r + √r^2 + h^2 ).

r = radius

h = height

The Pythagorean theorem, a^2 + b^2 = c^2, will be needed to find the height.

Plug in the values.

a(unknown)^2 + 6^2 = 15^2

A + 36 = 255

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*PEMDAS*

A = 3.14 × 6 ( 6 + √36 + 187.69 )

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Theo had a balance of -4 in his savings account. After making a deposit , he has $25 in his account . What is the overall change

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Theos initial balance in his savings account = -$4
Final balance after making a deposit = $25
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3 years ago

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Likurg_2 [28]

Answer:

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

To which set or sets does the number 12 belong? real numbers and natural numbers only real numbers, whole numbers, and integers

almond37 [142]

First off, let's take a look at what these numbers are:

Real numbers: It can be any numbers,both rational and irrational.

Natural numbers: The number has to be integer and positive.

Integers: A number without fraction or demical place.

Whole number: The number has to be natural and cannot be negative.

Therefore, as 12 is a positive number with no demical place or fraction, it is real numbers,integers, whole numbers, and natural numbers.

Hope it helps!

5 0

3 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{2};$
$5\cdot 4=20=\overline{7};$
$5\cdot 5=25=\overline{12};$
$5\cdot 6=30=\overline{4};$
$5\cdot 7=35=\overline{9};$
$5\cdot 8=40=\overline{1};$
$5\cdot 9=45=\overline{6};$
$5\cdot 10=50=\overline{11};$
$5\cdot 11=55=\overline{3};$
$5\cdot 12=60=\overline{8}.$

The multiplicative inverse of 5 in $Z_{13}$ is 8.

8 0

4 years ago