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Savatey [412]
3 years ago
8

What is the common difference between successive terms in the sequence? 2, 8, 14, 20, 26, ... –6 –4 4 6

Mathematics
2 answers:
Alex777 [14]3 years ago
8 0

Answer:

6

Step-by-step explanation:

Ainat [17]3 years ago
8 0

Answer:

6

Step-by-step explanation:

2+6=8

8+6=14

14+6=20

etc.

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What is the simplest form of the expression below? <br><br> -2x²(3x²-2x-6)
nirvana33 [79]

Answer:

   

Solution Given:

To find the simplest form we need to open bracket

-2x²(3x²-2x-6)

-2x²*3x²-2x²*(-2x) -2x²*(-6)\

-6x^{4}+4x^{3}+12x^2 is  a required answer.

7 0
2 years ago
This table displays the height of water as a pool is being filled. A 2-column table with 4 rows. Column 1 is labeled Time (minut
Law Incorporation [45]

Answer:1. 0.35. 0.35

Step-by-step explanation:

I did the question on edgenuity

6 0
3 years ago
Which set of coordinate pairs do NOT represent a linear function?
White raven [17]

Answer:

I'm pretty sure it is the second one

Step-by-step explanation:

7 0
3 years ago
Find the area of the shape
MAVERICK [17]

Answer:

A=42.5

Step-by-step explanation:

First you split this shape into a square and a triangle.

The area of the square is 5✖️5=25.

Then, there is a triangle left.

We do not know about the hypotenuse, but the sides are 5 and 7.

5✖️7=35/2<-- because it is a triangle. =17.5

You add both areas, and you get the total of 42.5.

Hope this helps!

3 0
3 years ago
Discrete Math
andrezito [222]

Answer:

Part c: Contained within the explanation

Part b: gcd(1200,560)=80

Part a: q=-6         r=1

Step-by-step explanation:

I will start with c and work my way up:

Part c:

Proof:

We want to shoe that bL=a+c for some integer L given:

bM=a for some integer M and bK=c for some integer K.

If a=bM and c=bK,

then a+c=bM+bK.

a+c=bM+bK

a+c=b(M+K) by factoring using distributive property

Now we have what we wanted to prove since integers are closed under addition.  M+K is an integer since M and K are integers.

So L=M+K in bL=a+c.

We have shown b|(a+c) given b|a and b|c.

//

Part b:

We are going to use Euclidean's Algorithm.

Start with bigger number and see how much smaller number goes into it:

1200=2(560)+80

560=80(7)

This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.

Part a:

Find q and r such that:

-65=q(11)+r

We want to find q and r such that they satisfy the division algorithm.

r is suppose to be a positive integer less than 11.

So q=-6 gives:

-65=(-6)(11)+r

-65=-66+r

So r=1 since r=-65+66.

So q=-6 while r=1.

3 0
3 years ago
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