The first thing you must do is to calculate the weight of the gravel (w) that the truck holds (7.5 yards³). So, you have:
If the weight of 1 yard³ is 1.48 tons, then the weight of 7.5 yards³ is:
w=7.5x1.48 tons
w=11.1 tons
The problem says that the gravel will be placed in containers that each hold 3.7 tons of gravel,so, If they need 1 cotainer to place 3.7 tons, how many containers they need to place 11.1 tons?
1 container-------3.7 tons of gravel
x-------11.1 tons of gravel
x=(11.1x1)/3.7
x=11.1/3.7
x=3 containers
H<span>ow many containers of this size are needed to hold all the gravel from one truck?
</span>
The answer is: 3 containers.
An angle adjacent to BOC would be COD or BAC.
Answer:
A) 10,560 ft. B) 32 more laps.
Step-by-step explanation:
A) Four laps around a track is equal to one mile, and there are 5,280 feet in one mile. If Roger ran eight laps, he ran two miles. Therefore: 5,280 ft. times 2, is equal to 10,560 ft.
B) We know that Roger ran two miles Monday. We also know that four laps around a track is equal to one mile. In order to run 10 miles, he would have to run 40 laps, and since he already ran 8, we can subtract that from 40. You are left with 32 more laps.
Answer:
which is the volume of the water
it implies , volume=l*b*h
50m*25m*2m
2500m'3
