Answer:
c. f(x) x+1/x-1
Step-by-step explanation:
To answer this question, we need to check each answer one by one until we find the right one.
y = (x+6)/(x-6)
switch x and y
x = (y+6)/(y-6)
solve for y
x(y-6) = y+6
xy - 6x = y+6
y(x-1) = 6x+6
y = (6x+6) /(x-1) = 6(x+1)/(x-1)
f^-1(x) = 6(x+1)/(x-1)
y = (x+2)/(x-2)
switch x and y
x = (y+2)/(y-2)
solve for y
x(y-2) = y+2
xy -2x = y+2
y(x-1) = 2x+2
y = (2x+2)/(x-1)
f^-1(x) = 2(x+1)/(x-1)
y = (x+1)/(x-1) ------ correct one
switch x and y
x = (y+1)/(y-1)
solve for y
x(y-1) = y+1
xy - x = y+1
y(x-1) = x+1
y = (x+1)/(x-1)
f^-1(x) = (x+1)/(x-1)
f(x) = f^-1(x)
Answer:
Step-by-step explanation:
a. Profit, p, earned from selling x hats when hat will be sold for $12 each:
p = 12x
b. To recover the cost of making the 200 hats which is $1500, profit, p >= cost:
p = 12x >= 1500
x >= 1500/12 = 12.5
So the minimum number of hats that must be sold = 13
c. New hat price = $15 so p = 15x
p = 15x >= 1500
x >= 1500/15 = 10
So the new minimum = 10 which is 3 fewer.
Yes based on ja 82 and it can be added
The answer to this is 500 my friend. 10 times 10 equals 100. 100 times 5 equals 500. hope this helps:)
Answer:
MY=80
Step-by-step explanation:
MX=MY ( since M is the midpoint)
2x+10=3x-5
10+5=3x-2x
15=x
MX+MY=MX
2x+10+3x-5=MY
2(15)+10+3(15)-5=MY
MY=80
