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3 years ago

If two lines are perpendicular to each other their slopes are

Mathematics

1 answer:

Anarel [89]3 years ago

3 0

Positive slope and negative slope so one line is negative and the other is positive

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Solve the system of linear equations below. <br><br> X+y=4<br> 2x+3y=0

deff fn [24]

X + y = 4...x = 4 - y

2x + 3y = 0
2(4-y) + 3y = 0
8 - 2y + 3y = 0
-2y + 3y = 0 - 8
y = -8

x + y = 4
x - 8 = 4
x = 4 + 8
x = 12

solution is : (12,-8)

7 0

3 years ago

Read 2 more answers

You multiply a number by 3 subtract 6 then add 2 the results is 20 what's the number

e-lub [12.9K]

You multiply a number by 3 subtract 6 then add 2 the results is 20

what's the number ?

Let the number = x

multiply a number by 3

so, it becomes 3x

subtract 6 , so, 3x - 6

then add 2

so, 3x - 6 + 2

The result will be 20

So,

3x - 6 + 2 = 20

solve for x

3x - 4 = 20

Add 4 to both sides

3x - 4 + 4 = 20 + 4

3x = 24

Divide both sides by 3

3x/3 = 24/3

So,

x = 8

5 0

1 year ago

4) What type of sequence is shown: 1, 2, 4, 7, 10,...

KIM [24]

Answer:

Stohr sequence

Step-by-step explanation:

Let a_1=1 and define a_(n+1) to be the least integer greater than a_n which cannot be written as the sum of at most h>=2 addends among the terms a_1, a_2, ..., a_n. This defines the h-Stöhr sequence

4 0

2 years ago

What is the value of (4-2)^3-3X4

Mazyrski [523]

<h2>Answer:</h2>

$3 x^{4}-8=0$

<h2>Given: </h2>

$(4-2)^{3}-3 x^{4}$

<h2>Step-by-step explanation:</h2>

In this problem, we need to find the value of the given expression for which we need to simplify the given expression.

$\Rightarrow(4-2)^{3}-3 x^{4}=0$

We need to solve the numbers within the parentheses.

$\Rightarrow(2)^{3}-3 x^{4}=0$

We can bring the constant one side and variables another side.

$\Rightarrow 8=3 x^{4}$

Taking fourth root for ‘8’ and ‘3’ will give numbers which are very tough to solve further.

Since, we cannot solve the above equation further. The value of the given equation remains,

$\therefore 3 x^{4}-8=0$

6 0

3 years ago

Given that x and y are positive integers, solve the equation x² - 4y² = 13

zvonat [6]

<h3>Answer: x = 7 and y = 3</h3>

=====================================================

Explanation:

Apply the difference of squares rule

x² - 4y² = 13

x² - (2y)² = 13

(x - 2y)(x + 2y) = 13

Since x and y are positive integers, this means x-2y and x+2y are both integers as well.

The value 13 is prime. Its only factors are 1 and 13

Since the above equation shows 13 factoring into x-2y and x+2y, then we have two cases:

A) x-2y = 1 and x+2y = 13
B) x-2y = 13 and x+2y = 1

----------------

Let's consider case A

We have this system of equations

$\begin{cases}x-2y = 1\\x+2y = 13\end{cases}$

Add the equations straight down

x+x becomes 2x
-2y+2y becomes 0y = 0 which goes away
1+13 becomes 14

Therefore we have 2x = 14 solve to x = 7

From here, plug this into either equation to solve for y

x-2y = 1

7 - 2y = 1

-2y = 1-7

-2y = -6

y = -6/(-2)

y = 3

You should get the same result if you used x+2y = 13

----------------

Since we've found that x = 7 and y = 3, notice how case B is not possible

Example: x-2y = 13 becomes 7-2(3) = 13 which is false.

Also, x+2y = 1 would turn into 7+2(3) = 1 which is also false.

-----------------

Let's check those x and y values in the original equation

x² - 4y² = 13

7² - 4*(3)² = 13

49 - 4(9) = 13

49 - 36 = 13

13 = 13

The answer is confirmed.

4 0

2 years ago