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kondaur [170]
3 years ago
5

Find the value of the trigonometric ratio, cos M.

Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0

Answer:

The answer is option D.

Step-by-step explanation:

cos M = adjacent / hypotenuse

From the picture

b is the adjacent

x is the hypotenuse

so

cos M = b/x

Hope this helps you

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The weight of an object on a particular scale 155. 2lbs the measured weight May very from the actual weight by the most 0.4 lbs
zavuch27 [327]

Answer:

154.8-155.6

Step-by-step explanation:

155.2-.4=154.8 or maybe its more in that case the most it could be is 155.2+.4=155.6

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4 years ago
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I wasn't sure what properties the assignment was looking for... Let me know if you have any other questions!

6 0
3 years ago
Elena is paid a constant rate for each hour she works. The table shows the amounts of money that Elena earned for various amount
Nikolay [14]

Constant rates are used to illustrate linear functions.

  • The average rate of change is $9.0 per hour
  • The function that models the table is: \mathbf{f(x) = 9x }
  • The amount earned in 7.5 hours is $67.5

<u>(a) The average rate of change</u>

This is calculated using:

\mathbf{Rate = \frac{y_2 -y_1}{x_2 -x_1}}

So, we have:

\mathbf{Rate = \frac{31.5-22.50}{3.5 - 2.5}}

\mathbf{Rate = \frac{9}{1.0}}

\mathbf{Rate = 9.0}

Hence, the average rate of change is $9.0 per hour

<u>(b) A function that models the table of values</u>

Let x represent hours, and y represent the earnings.

So, we have:

\mathbf{y =m (x - x_1) + y_1}

Where:

m =Rate = 9.0

So, we have:

\mathbf{y = 9(x - 2.5) + 22.5}

Expand

\mathbf{y = 9x - 22.5 + 22.5}

\mathbf{y = 9x }

Represent as a function

\mathbf{f(x) = 9x }

Hence, the function that models the table is: \mathbf{f(x) = 9x }

<u>(c) Amount earned for 7.5 hours</u>

This means that x = 7.5

So, we have:

\mathbf{f(7.5) = 9 \times 7.5 }

\mathbf{f(7.5) = 67.5}

Hence, the amount earned in 7.5 hours is $67.5

Read more about constant rates at:

brainly.com/question/23184115

4 0
2 years ago
Simplify: (c+4/c^2+5x+6)/(3c^2+12c/2c^2+5c-3)
juin [17]
(c+4/c^2+5c+6)/(3c^2+12c/2c^2+5c-3)= (c+4)/(c^2+5c+6) Multiplied by (2c^2+5c-3)/3c^2+12c= 2c^3+5c^2-3c+8c^2+20c-12/3c^4+12c^3+15c^3+60c^2+18c^2+72= 2c^3+13c^2+17c-12/3c^4+27c^3+78c^2+72c
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