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Alja [10]
3 years ago
10

X/60 equal 25/100 who at does that equal

Mathematics
1 answer:
wel3 years ago
8 0

Answer:

15/60.

Step-by-step explanation:

25/100 is 1/4 so a 4th of 60 would be 15. 1/4 = 1/4

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Answer:

E. 5√4^3

Step-by-step explanation:


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4 years ago
******Please help me help please help me ******
lisov135 [29]

9514 1404 393

Answer:

  -19/7

Step-by-step explanation:

If the variation is direct, any multiplier of the m-value will also multiply the f-value.

 old value × 1/7 = new value

 m: 14 × 1/7 = 2

 f: -19 × 1/7 = -19/7

The new value of f is -19/7.

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3 years ago
55 km/h converted to miles per hour
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<span>55 km/h converted to miles per hour:

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4 0
3 years ago
The ages of a random sample of five university professors are 39, 54, 61, 72, and 59. Using this information, find a 99% confide
blsea [12.9K]

Answer:

38.898 \leq \sigma^2 \leq 2792.356

Now we just take square root on both sides of the interval and we got:

6.237 \leq \sigma \leq 52.843

Step-by-step explanation:

Data given and notation

34,59,61,71,59

We can calculate the sample standard deviation with the following formula:

s^2= \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

s= \sqrt{s^2}

s=12.021 represent the sample standard deviation

\bar x represent the sample mean

n=5 the sample size

Confidence=99% or 0.99

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=5-1=4

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.005,4)" "=CHISQ.INV(1-0.005,4)". so for this case the critical values are:

\chi^2_{\alpha/2}=14.860

\chi^2_{1- \alpha/2}=0.207

And replacing into the formula for the interval we got:

\frac{(4)(12.021)^2}{14.860} \leq \sigma^2 \leq \frac{(4)(12.021)^2}{0.207}

38.898 \leq \sigma^2 \leq 2792.356

Now we just take square root on both sides of the interval and we got:

6.237 \leq \sigma \leq 52.843

3 0
3 years ago
Read 2 more answers
20 points!~ And thanks if you help me.
Oduvanchick [21]

Answer:

A : w+6=32 |-6

w=26

B:w-6=32 |+6

w=38

8 0
3 years ago
Read 2 more answers
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